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larisa [96]
3 years ago
10

A bag contains two steel balls and five brass balls. The total weight of the bag is 13 pounds. If two steel balls are added and

two brass balls are removed, the bag’s weight decreases to 12 pounds. If s is the weight of a steel ball and b is the weight of a brass ball, the system of linear equations representing this situation is . Solving the system of linear equations, the weight of a steel ball is , and the weight of a brass ball is . NextReset
Mathematics
1 answer:
nlexa [21]3 years ago
5 0

x = the weight of one steel ball y = the weight of one brass ball 2x + 5y = 13 (2 + 2)x + (5 - 2)y = 12 by solving the above system of equations we find:

x = 1.5 lbs y =2 lbs one steel ball weighs 1.5 lbs.one brass ball weighs 2 lbs.

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2) Complete the table.<br>x<br>20<br>200<br>2000<br>15<br>20​
Dimas [21]
I think it’s 25 but I’m not too sure
3 0
2 years ago
Use the box method to distribute and simplify (-5x-2)(-2x^2+6x).
Mkey [24]

Answer:

10x^{3} - 26x^{2} - 12x

Step-by-step explanation:

1)  Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.

10x^{3} - 30x^{2} + 4x^{2} -12x

2)  Collect like terms.

10x^{3} + (-30x^{2} +4x^{2} )-12x

3) Simplify.

10x^{3} - 26x^{2} -12x

Therefor, the answer is, 10x^3 - 26x^2 - 12x.

3 0
2 years ago
Pleaseeeeeeehelppppppp!!!
il63 [147K]

Answer: I think it it 5 if

Step-by-step explanation:

If I am wrong I am very sorry and if I am right could you please make me brainliest please?

4 0
2 years ago
HELP IM IN DESPERATE NEED!!!<br> What is the solution to this system of equations?
Paladinen [302]

[Given]

{ x + y = 6

{ x = y + 4

[Plug-in our x value & solve]

[Given] x + y = 6

[ Plug-in] (y + 4) + y = 6

[Distribute] y + 4 + y = 6

[Combine like terms] 2y + 4 = 6

[Subtract 4 from both sides] 2y = 2

[Divide both sides by 2] y = 1

[Answer]

Third option - (5, 1)

-> You do not need to solve for x since this is the only option that has y = 1, but to solve for x we would do y + 4 = 1 + 4 = 5, so this answer fully checks correctly

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

     ★ Also please leave the rating you think I deserve (It helps other users as well as myself)

- Heather

6 0
2 years ago
Given f (x) = startlayout enlarged left-brace first row 3 startroot 2 x minus 1 endroot, for x less-than-or-equal-to 2 second ro
qwelly [4]

<u>These 2 equations has </u><u>no solution</u><u> and the equations are </u><u>independent</u><u> </u><u>of each other.</u>

What is liner equation with two variable?

  • An equation is said to be linear equation in two variables if it is written in the form of ax + by + c=0, where a, b & c are real numbers and the coefficients of x and y, i.e a and b respectively, are not equal to zero.
  • For example, 10x+4y = 3 and -x+5y = 2 are linear equations in two variables.

-10x² -10y² = -300 ----a

5x² + 5y² = 150 ---- b

While trying to solve this,

We can multiply the eq. b by 2 so we will get eq. c and then add to eq. a we will get 0 as the solution.

10x² + 10y² = 300 ----c

-10x² -10y² = -300 ---a

<u>Everything cutoff, we will </u><u>get 0</u><u>, and there is no solution to these equations.</u>

Learn more about liner equation with two variable brainly.com/question/16933755

#SPJ4

8 0
2 years ago
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