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3 years ago

A rectangular prism has a volume of 378 cubic inches the area of the base is 42 square inches what is the height

Mathematics

1 answer:

barxatty [35]3 years ago

7 0

Answer:

9 inches.

Step-by-step explanation:

The formula for the volume of a rectangular prism is base x height. So if the volume is 378, and the base is 42, you would use the equation 378/42 to find the height. 378/42 is 9. Therefore, the height is 9 inches.

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4. Find the value of the expression below for r=4 and t=2.

Katen [24]

Answer:

(a) 9

Step-by-step explanation:

$\sf t^3 - r + 20 \div r$

substitute r = 4, t = 2

$\sf (2)^3 - 4 + 20 \div 4$

simplify

$\sf (2)^3 - 4 + 5$

cubic of 2 is 8

$\sf 8 - 4 + 5$

simplify

$\sf 9$

5 0

2 years ago

Read 2 more answers

Can you pls help me thank you have a good day

expeople1 [14]

Answer:

the slope is 3/1 so if the point before your answer is (2,6) the add 3 to six and 1 to 2 and your answer is (3,9).

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8 0

3 years ago

Read 2 more answers

Kaci bought a birthday cake like the one shown below. If a=5inches,b=5inches,c=10 inches, and d=3inches what is the volume of th

Gnom [1K]

Answer:

75+150=225 in^2

Step-by-step explanation:

Separate each layer.

Area1+Area2= Total area

A1= a*b*d

A2=a*c*d

A1=5*5*3=75 in^2

A2=5*10*3=150 in^2

75+150=225 in^2

7 0

3 years ago

Find the next 3 terms in the geometric sequence -36, 6, -1, 1/6, ...

timama [110]

we are given

geometric sequence -36, 6, -1, 1/6, ...

first term is -36

$a_1=-36$

now, we can find common ratio

$r=\frac{6}{-36}$

$r=-\frac{1}{6}$

now, we can find nth term

$a_n=a_1(r)^{n-1}$

now, we can plug values

and we get

$a_n=36(-\frac{1}{6})^{n-1}$

now, we can find 5th term , 6th term, 7th term

fifth term:

$a_5=36(-\frac{1}{6})^{4}$

$a_5=\frac{1}{36}$

sixth term:

$a_6=36(-\frac{1}{6})^{5}$

$a_6=-\frac{1}{216}$

seventh term:

$a_7=36(-\frac{1}{6})^{6}$

$a_7=\frac{1}{1296}$

so, next terms are

$a_5=\frac{1}{36}$ , $a_6=-\frac{1}{216}$

, $a_7=\frac{1}{1296}$ .............Answer

6 0

3 years ago

Find a polynomial function of degree 3 with 2, i, -i as zeros.

sergiy2304 [10]

Answer:

$p(x)= x^3-2x^2+x-2$

Step-by-step explanation:

Here we are given that a polynomial has zeros as 2 , i and -i . We need to find out the cubic polynomial . In general we know that if $\alpha , \ \beta \ \& \ \gamma$ are the zeros of the cubic polynomial , then ,