Given:
The system of equations is
To find:
The missing value for which the given system of equations have infinitely many solutions.
Solution:
Let the missing value be k.
We have,
Taking all the terms on the left side, the given equations can be rewritten as
The system of equations 
and 
have infinitely many solutions if
We have,
Now,
On cross multiplication, we get
Therefore, the missing value is -10.
The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
Learn more on polynomial here: brainly.com/question/2833285
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Answer:
x = 46
Step-by-step explanation:
Given 2 secants from an external point to the circle, then
The product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant, that is
2(2 + x) = 6(6 + 10)
2(2 + x) = 6 × 16 = 96 ( divide both sides by 2 )
2 + x = 48 ( subtract 2 from both sides )
x = 46
Answer:
9
Step-by-step explanation:
9 is the correct answer.
