f(x)=lnx
y=f(x)
dy/dx= 1/x
tangent at (x,y) has slope 1/x
eqn of tangent is y = mx + c
since the tangent passes through origin, c=0
substitute y = lnx and m= 1/x to above eqn
lnx = 1
x=e
y=lne=1
A.) x + 8 < 14
-8 -8
x < 6
b.) x - 12 >/= 5.7
+12 +12
x >/= 17.7
Might be A not sure though
Answer:
Did you ask a question? I just checked your profile to see if you posted any but i dont see anything except this
Step-by-step explanation:
Answer:
-7x/6
Step-by-step explanation:
x/2-5x/3
Taking LCM
3x/6-10x/6
(3x-10x)/6
-7x/6
