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mario62 [17]
4 years ago
9

Which of the following is a graph of y=3/2x2

Mathematics
1 answer:
Tanya [424]4 years ago
8 0
Here is a table that you can use to graph y=3/2x^2
x -2, -1, 0, 1, 2
y 6, 1.5, 0, 1.5, 6
You might be interested in
Need helpplz i struggling ​
Zolol [24]

7^2+18^2=49+324

49+324=373

19.31^2 would be your answer

6 0
3 years ago
According to a study conducted in one city, 39% of adults in the city have credit card debts of more than $2000. A simple random
Butoxors [25]

Answer:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean \mu = 0.39 and standard deviation s = 0.0488

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

p = 0.39, n = 100

Then

s = \sqrt{\frac{0.39*0.61}{100}} = 0.0488

By the Central Limit Theorem:

The sampling distribution of the sample proportion of adults who have credit card debts of more than $2000 is approximately normally distributed with mean \mu = 0.39 and standard deviation s = 0.0488

5 0
3 years ago
What is the value of x in the equation 2x+3y=36 when y=6
Lady_Fox [76]
2x+3y=36
2x=36-3y
y=6
2x=36-3*6
2x=36-18
2x=18
x=18:2
x=9
7 0
3 years ago
A screening test for a certain disease is used in a large population of people of whom 1 in 1000 actually have the disease. Supp
sertanlavr [38]

Answer:

P(D/T)=5.05*10^{-6}

Step-by-step explanation:

Let's call D the event that a person has the disease, D' the event that a person doesn't have the disease and T the event that the person tests negative for the disease.

So, the probability P(D/T) that a randomly chosen person who tests negative for the disease actually has the disease is calculated as:

P(D/T) = P(D∩T)/P(T)

Where P(T) = P(D∩T) + P(D'∩T)

So, the probability P(D∩T) that a person has the disease and the person tests negative for the disease is equal to:

P(D∩T) = (1/1000)*(0.005) = 0.000005

Because 1/1000 is the probability that the person has the disease and 0.005 is the probability that the person tests negative given that the person has the disease.

At the same way, the probability P(D'∩T) that a person doesn't have the disease and the person tests negative for the disease is equal to:

P(D'∩T) = (999/1000)*(0.99) = 0.98901

Finally, P(T) and P(D/T) are equal to:

P(T) = 0.000005 + 0.98901 = 0.989015

P(D/T) = 0.000005/0.989015 = 5.05*10^{-6}

8 0
3 years ago
17-||-9|+3|<br> Can anyone help me out?
zmey [24]

Answer:

Step-by-step explanation:

Step 1:

17 - 9 + 3

Step 2:

8 + 3

Answer:

11

Absolute Value turns everything positive.

Hope This Helps :)

7 0
3 years ago
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