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3 years ago

13

For each of the figures, write an absolute value equation to satisfy the given solution set.

2 answers:

Snowcat [4.5K]3 years ago

8 0

|x -4| -4 = 0
is one such equation.

Ksju [112]3 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

Suppose that the functions u and w are defined as follows.

jasenka [17]

Answer(there are assumptions for this answer that you need to confirm and look at):

Assumptions: $u(x)=x^2+3$ and $w(x)=\sqrt{x+2}$

Answer if the operation is multiplication:

If you meant a closed dot which is the symbol for multiplication.

$(u \cdot w)(2)=14$

$(w \cdot u)(2)=14$

Answer if the operation is composition:

If you meant an open dot which is the symbol for composition.

$(u \circ w)(2)=7$

$(w \circ u)(2)=3$

Note: I don't know if you actually meant $w(x)=\sqrt{x+2}$ or if $w(x)=\sqrt{x}+2$ . Please let me know one way or the other.

Step-by-step explanation:

If we assume the functions are:

$u(x)=x^2+3$

$w(x)=\sqrt{x+2}$

$u \cdot w=w \cdot u$ since multiplication is commutative.

$u(2)=2^2+3$

$u(2)=4+3$

$u(2)=7$

$w(2)=\sqrt{2+2}$

$w(2)=\sqrt{4}$

$w(2)=2$

We are asked to find $(u \cdot w)(2)$ and $(w \cdot u)(2)$ .

The order doesn't matter in multiplication.

$(u \cdot w)(2)$

$u(2) \cdot w(2)$

$7 \cdot 2$

$14$

$(w \cdot u)(2)$

$w(2) \cdot u(2)$

$2 \cdot 7$

$14$

Now you might have meant composition which symbolized with an open circle, not a closed one.

$(u \circ w)(2)$

$u(w(2))$

$u(2)$ since $w(2)=2$

$2^2+3$

$4+3$

$7$

$(w \circ u)(2)$

$w(u(2))$

$w(7)$ since $u(2)=7$

$\sqrt{7+2}$

$\sqrt{9}$

$3$

6 0

3 years ago

Please help me w the equation and please don’t take advantage of the points.

kifflom [539]

Answer:

y=2x+4

Step-by-step explanation:

Im pretty sure that is correct.

5 0

3 years ago

Read 2 more answers

The cheerleaders at Lake High School launch T-shirts into the crowd every time the Lakers score a touchdown. The height of the T

Mamont248 [21]

the anser is c because i dont know

6 0

2 years ago

Solution to equation c-4>2(c)

inna [77]

C-4>2c
minus c from both sides
c-c-4>2c-1c
0-4>c
c<-4
c can be any number less than -4

3 0

3 years ago

Rewrite in mathematical language. Every negative integer J is less than or equal to its inverse.

Luda [366]

Answer:

$-J \leq J$

Step-by-step explanation:

Given

Negative integer J

Required

Represent as an inequality of its inverse

The question didn't state if it's additive inverse or multiplicative inverse;

<em>Since the question has to do with negation, I'll assume it's an additive inverse</em>

<em></em>

The inverse of -J is +J

To represent as an inequality (less than or equal), we have:

$-J \leq +J$

Solving further, it gives

$-J \leq J$

3 0

3 years ago