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eduard
3 years ago
13

Which of the graphs below would result if you made the leading term of the following function negative?

Mathematics
2 answers:
lukranit [14]3 years ago
6 0

I believe the answer is Graph D

Furkat [3]3 years ago
4 0

Answer:

Graph D

Step-by-step explanation:

Given is the function

f(x) =5x^3+x-8

When leading term is changed to negative we get new function

g(x) = -5x^3+x-8

To find y intercept:

Put x=0

Y intercept = 5(0)+0-8 =-8

Since only graph D has y intercept -8, we get graph D is the answer.

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First, check to see which graph has a line going through the point (2,3). B and D are the only ones that have lines going through (2,3) (A comes close but it is not quite).

Next, you need to see which line would be parallel to the equation 3x-y=2. When two lines are parallel, they have the same slope. You have to turn that equation into point-slope formula (y=mx+b with m being the slope and b being the y-intercept). First, subtract 3x from both sides. You will then get -y=-3x+2. Then y needs to be alone (right now it has a -1 attached). Divide both sides by -1 to get y=3x-2. The number in front of the x is the slope, in this case, 3 or 3/1 (we do not care about the y-intercept, it will not help us in this problem since we are looking for a line parallel to this equation and so our line will not have the same y-intercept as this other equation). Since the line in parallel to that equation, we know that this line also has a slope of 3/1. Find the line between B and D that has a slope of 3/1, you get B (the line goes up 3 over 1).

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200 - 30 = 170

The answer to the question is 170.

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2 years ago
Read 2 more answers
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