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The total amount of money is 65x + 10 cents.
<h3>Sum of coins</h3>
Given the following coins value
x dimes, (x+2) nickels, and 2x quarters
If value of a dime is 10 cents, nickel is 5 cents, and a quarter is 25 cent, the the total coin is cent is expressed as 10x + 5(x + 2) + 25(2x)
Total in cents. = 10x + 5(x + 2) + 25(2x)
Total in cents = 10x + 5x + 10 + 50x
Simplify
Total in cents = 65x + 10
Hence the total amount of money is 65x + 10 cents.
Learn more on cents to dimes here: brainly.com/question/6810598
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<h3><em><u>A. 4xy-16</u></em></h3>
<em><u>=4(xy−4)</u></em>
<h3 /><h3><em><u>B. xy+2xy-x</u></em></h3>
<em><u>3xy−x</u></em>
<em><u>=x(3y−1)</u></em>
<h3><em><u>C. 2x²-18x+12</u></em></h3>
<em><u>2x²</u></em><em><u>−18x+12</u></em>
<em><u>=2(</u></em><em><u>x²</u></em><em><u>−9x+6)</u></em>
<h3><em><u>D. 5xy+20x-9y-36</u></em></h3>
<em><u>5xy+20x−9y−36</u></em>
<em><u>=(y+4)(5x−9)</u></em>
One way of doing it is by using the properties of summing things, like factoring out the minus sign:
<span><span>∑<span>n=2</span>8</span><span>−(n−5)</span>=−<span>∑<span>n=2</span>8</span><span>(n−5)
</span></span>
and splitting it up into two parts and again factor
<span>=−<span>(<span><span>∑<span>n=2</span>8</span><span>n−5<span>∑<span>n=2</span>8</span>1</span></span>)
</span></span>
The last sum is just counting how many numbers there are from 2 to 8, which is 7 (you can do it on your fingers). The first one can be calculated fast if we are clever and use this identity:
<span><span>∑<span>n=1</span>m</span>n=<span><span>m(m+1)</span>2
</span></span>
So what we get is
<span><span>=−<span>(<span>−1+<span><span>8(8+1)</span>2</span>−7</span>)</span>=8−72/2=8−36=−28.</span></span>
