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sasho [114]
4 years ago
5

Reflect (7, 3) in (a) the x-axis and (b) the y-axis

Mathematics
1 answer:
Kisachek [45]4 years ago
3 0

Answer:

In x-axis: (7,-3), In y-axis: (-7,3)

Step-by-step explanation:

The rule of the reflection of a point across the x-axis is as shown:

The reflection of the point (x,y) across the x-axis is given by (x,-y).

The point given to us is (7,3), when reflected across the x-axis we get:

(x,-y)=(7,-3)

Now, when a point (x,y) is reflected across the y-axis we get the point (-x,y).

So when the point (7,3) is reflected across the y-axis we get: (-x,y)=(-7,3).

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Suppose F⃗ (x,y)=(x+3)i⃗ +(6y+3)j⃗ . Use the fundamental theorem of line integrals to calculate the following.
Scorpion4ik [409]

In order to use the fundamental theorem of line integrals, you need to find a scalar potential function - that is, a scalar function <em>f(x, y)</em> for which

grad <em>f(x, y)</em> = <em>F</em><em>(x, y)</em>

This amounts to solving for <em>f</em> such that

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Differentiating with respect to <em>y</em> gives

∂<em>f</em>/∂<em>y</em> = d<em>g</em>/d<em>y</em> = 6<em>y</em> + 3

Solving for <em>g</em> gives

<em>g</em> = ∫ (6<em>y</em> + 3) d<em>y</em> = 3<em>y</em> ^2 + 3<em>y</em> + <em>C</em>

and hence

<em>f(x, y)</em> = 1/2 <em>x</em> ^2 + 3<em>x</em> + 3<em>y</em> ^2 + 3<em>y</em> + <em>C</em>

<em />

(a) By the fundamental theorem, the integral of <em>F</em> along any path starting at the point <em>P</em> (1, 0) and ending at <em>Q</em> (3, 3) is

∫ <em>F</em><em>(x, y)</em> • d<em>r</em> = <em>f</em> (3, 3) - <em>f</em> (1, 0) = 99/2 - 7/2 = 46

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∫ <em>F</em><em>(x, y)</em> • d<em>r</em> = <em>f</em> (1, 0) - <em>f</em> (0, 0) = 7/2 - 0 = 7/2

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