Answer:
8:45
Step-by-step explanation:
5x48=240 sec
240 sec = 4 min
8:49-4min= 8:45
Step-by-step explanation:
<u>Our problem:</u>
How to solve?
Find the reciprocal (opposite) of 4/5, then multiply. Simplify if necessary.
<u>Find the reciprocal:</u>
<u>Multiply:</u>
<u>Simplify:</u>
5/6 is your answer.
<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
Answer:
what grade you in
Step-by-step explanation:
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Answer:
Step-by-step explanation:
To find 
, we need to eliminate 
in this system of equations:
(1)
(2)
From (1) and (2):
Then, we equalize both expressions and solve for :
