This is a combination problem.
Given:
12 students
3 groups consisting of 4 students.
Mark can't be in the first group.
The combination formula that I used is: n! / r!(n-r)!
where: n = number of choices ; r = number of people to be chosen.
This is the formula I used because the order is not important and repetition is not allowed.
Since Mark can't be considered in the first group, the value of n would be 11 instead of 12. value of r is 4.
numerator: n! = 11! = 39,916,800
denominator: r!(n-r)! = 4!(11-4)! = 4!*7! = 120,960
Combination = 39,916,800 / 120,960 = 330
There are 330 ways that the instructor can choose 4 students for the first group
9 quarts of red and 3 quarts of yellow. do 3/4 times 12 and 1/4 times 12
Answer:
4
Step-by-step explanation:
the correct answer is number 4
if X = 2 ==> 2x -5 = 2(2) -5 = 4 - 5 = -1
9514 1404 393
Answer:
(a) M = 0.25n +100
Step-by-step explanation:
The distance between the dots on the graph is a rise of 1 grid square and a run of 2 grid squares. If we extend the sequence of dots to the left, we expect to place one at (0, 100). That is, the y-intercept of this function is 100 (eliminates choices C and D).
The rise of 1 grid square represents 25 kg, and the run of 2 grid squares represents 100 CDs. Then the slope of the function (rate of change) is ...
slope = rise/run = 25/100 kg/CD = 0.25
Then the equation describing the points on the graph will be ...
M = 0.25n +100
