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Andrej [43]
3 years ago
5

3x+2=x+10 what is the answer to this equation

Mathematics
2 answers:
marysya [2.9K]3 years ago
6 0

Answer:

x= 4

Step-by-step explanation:

Harrizon [31]3 years ago
3 0

Answer:

x=4

let me know if u need the steps

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How to do steps in a division problem of 616 divided by 2
leva [86]

Answer:

308

Step-by-step explanation:

616÷2 ***************************

3 0
3 years ago
Tyler surveys his classmates to determine the number and type of pets they have. The frequency table below shows this data.Based
kodGreya [7K]
I would saybar chart because it is a set amount of data
3 0
3 years ago
Read 2 more answers
Round to the nearest hundredth
Charra [1.4K]
Hey there,
1st hat = x
2nd hat = 2x
3x = $75.12
x= $75.12 / 3
  = $25.04
2x = $25.04 x 2
     =$50.08
     = $50.10 (round off)

Hope this helps ^_^

~Top
7 0
3 years ago
The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra
Snezhnost [94]
Let X denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by X_1,\ldots,X_{36}, each independently and identically distributed with distribution X_i\sim\mathcal N(26,7.2).

You want to find

\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)

Recall that if X\sim\mathcal N(\mu,\sigma), then the sampling distribution \overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right) with n being the size of the sample.

Transforming to the standard normal distribution, you have

Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}

so that in this case,

Z=6\dfrac{\overline X-26}{7.2}

and the probability is equivalent to

\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)
=\mathbb P(Z>1.481)\approx0.0693
5 0
3 years ago
Write a problem that can be solved by comparing feet and inches using a model.Include a solution.Explain why you are changing fr
Oduvanchick [21]
Change any number of feet to inches. Every foot is equal to 12 inches. So multiply the number of feet you have by 12. 
Ex. 5 feet= 60inches 
4 0
3 years ago
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