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sweet [91]
3 years ago
12

Please answer this correctly

Mathematics
2 answers:
natali 33 [55]3 years ago
8 0

Answer: 30

Step-by-step explanation:

Q1: 120

Q3: 150

To find the interquartile range, subtract Q1 from Q3, which is 150-120. Therefore, the interquartile range  of the kitten's weight, is 30

Mnenie [13.5K]3 years ago
5 0

Answer: 30 grams

Step-by-step explanation:

The interquartile range is the range within the boxed areaa. You subtract the minimum value from the maximum value.

150 - 120 = 30

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Answer:

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Step-by-step explanation:

There are 360 degrees total in this figure. Since 160 is already shown, we can subtract it from 360 to solve for x. 360 - 160 = 200. So, 200 degrees is split among the remaining values, which are 2 x's. Since each x has the same value, we can divide 200 evenly among the two of them. 200/2 = 100. So, x = 100.

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The answer is BC = 38.22 cm.

<u>Step-by-step explanation</u>:

We have, ∠BKD = 120° ,BK = 28 cm, Draw a perpendicular from point K on BC let it intersect at point M.  In right angled ΔBMK, ∠BKM=30° and BK = 28 cm

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