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GREYUIT [131]
3 years ago
11

For each of the questions, find the value of x. If necessary, round your answer to the nearest tenth. The figure is not drawn to

scale.
please please help! i have attached pictures.

1. a. 8
b. 5
c. 6
d. 10

2. a. 21.9
b. 181.3
c. 24
d. 13.5

3. a. 13
b. 26
c. 77
d. 38.5

Mathematics
1 answer:
Step2247 [10]3 years ago
3 0

Answer:

1. D

2. D

3. C

Step-by-step explanation:

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Some scientists believe alcoholism is linked to social isolation. One measure of social isolation is marital status. A study of
alexandr402 [8]

Answer:

1) H0: There is significant evidence of independence between marital status and diagnostic

H1: There is significant evidence of an association between marital status and diagnostic

2) The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

3) \chi^2 = \frac{(21-33.143)^2}{31.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

4) p_v = P(\chi^2_{2} >19.72)=0.00005222

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p values is lower than the significance level we have enough evidence to reject the null hypothesis at 5% of significance, and we can say that we have associated between the two variables analyzed.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                    Alcoholic    Undiagnosed Alcoholic     Not Alcoholic   Total

Married             21                         37                               58                  116

Not Married      59                        63                               42                  164

Total                  80                        100                             100                 280

Part 1

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is significant evidence of independence between marital status and diagnostic

H1: There is significant evidence of an association between marital status and diagnostic

The level os significance assumed for this case is \alpha=0.05

Part 2

The statistic to check the hypothesis is given by:

\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{80*116}{280}=33.143

E_{2} =\frac{100*116}{280}=41.429

E_{3} =\frac{100*116}{280}=41.429

E_{4} =\frac{80*164}{280}=46.857

E_{5} =\frac{100*164}{280}=58.571

E_{6} =\frac{100*164}{280}=58.571

And the expected values are given by:

                    Alcoholic    Undiagnosed Alcoholic     Not Alcoholic   Total

Married         33.143                    41.429                        41.429              116

Not Married  46.857                   58.571                        58.571              164

Total                  80                        100                             100                 280

Part 3

And now we can calculate the statistic:

\chi^2 = \frac{(21-33.143)^2}{31.143}+\frac{(37-41.429)^2}{41.429}+\frac{(58-41.429)^2}{41.429}+\frac{(59-46.857)^2}{46.857}+\frac{(63-58.571)^2}{58.571}+\frac{(42-58.571)^2}{58.571} =19.72

Part 4

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(2-1)(3-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.72)=0.00005222

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.72,2,TRUE)"

Since the p values is lower than the significance level we have enough evidence to reject the null hypothesis at 5% of significance, and we can say that we have associated between the two variables analyzed.

8 0
3 years ago
50 POINTS!!! HELP!!! What is the answer?
kobusy [5.1K]
Isn't this the NWEA?
3 0
3 years ago
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Nancy joined Movies Extraordinaire for a $8 fee and an agreement to pay $1.99 per movie she rents. The equation for her total co
Anna11 [10]
The answer is $57.75.

Step by Step:

Take the amount of movies ( x ) multiplied by the cost of each ( $1.99 ) and add the fee. ( $8 )
6 0
3 years ago
Problem situation: Bernie spends $6.50 on ingredients and cups for his lemonade stand. He charges $1.50 for each cup of lemonade
salantis [7]

Answer:

Answer:

18 cups.

Step-by-step explanation:

We are given that Bernie spends $6.50 on ingredients and cups for his lemonade stand. He charges $1.50 for each cup of lemonade. Inequality that represents this situation: .

To find number of cups x to make a profit of at least  $20 we will use our given inequality.

Therefore, in order to make a profit of at least $20 Bernie need to sell 18 cups of lemonade.

3 0
3 years ago
The endpoints of a line segment graphed on a Cartesian coordinate system are (4, 1) and (-2, -4). What are the coordinates of th
Masja [62]
The midpoint of (x1,y1) and (x2,y2) is (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

just average them


(4,1) and (-2,4)
the midpoint is  (\frac{4-2}{2},\frac{1-4}{2})=(\frac{2}{2},\frac{-3}{2})=(1,-1.5)
5 0
3 years ago
Read 2 more answers
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