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3 years ago

11

For each of the questions, find the value of x. If necessary, round your answer to the nearest tenth. The figure is not drawn to

scale.
please please help! i have attached pictures.

1. a. 8
b. 5
c. 6
d. 10

2. a. 21.9
b. 181.3
c. 24
d. 13.5

3. a. 13
b. 26
c. 77
d. 38.5

1 answer:

Step2247 [10]3 years ago

3 0

Answer:

1. D

2. D

3. C

Step-by-step explanation:

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Alexxx [7]

Answer:

LIMIT

The policy will pay for up to

$100,000 of damage to

another person's property.

The policy will pay only

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DEDUCTIBLE

The policyholder must pay

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PREMIUM

The policy offers coverage

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The policyholder must

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Step-by-step explanation:

LIMIT is the maximum amount an insurer will pay toward a covered claim

DEDUCTIBLE is the amount paid out of pocket toward a covered claim

PREMIUM is the amount paid regularly to keep the policy in force.

6 0

3 years ago

What rule is this, please answer correctly, please

hichkok12 [17]

Answer:

Reflection

Step-by-step explanation: It is reflection because it is the same thing just reflected

7 0

2 years ago

Read 2 more answers

What is the remainder of 10^2017 divided by 1001?

pashok25 [27]

Note: When I use the double equal sign, I mean the triple bar used with modular arithmetic

10^3 = 1000 == -1 (mod 1001)
10^3 == -1 (mod 1001)
(10^3)^672 == (-1)^672 (mod 1001)
(10^(3*672) == 1 (mod 1001)
10^2016 == 1 (mod 1001)
10*10^2016 == 10*1 (mod 1001)
10^2017 == 10 (mod 1001)

Final Answer: 10

5 0

3 years ago

A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to

melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

$P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}$

Mean of X:

$E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42$

Variance of X:

$E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}$

$var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58$

5 0

3 years ago

Insert a rational number and an irrational number between -2/5 and 1/2

qwelly [4]

Answer:

Step-by-step explanation:

if you can pick any numbers you want then:

rational could be: 0.25 or 1/4

irrational could be: 2/7

6 0

3 years ago