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vovangra [49]
3 years ago
15

Number 13 show work and show work for number 12 thanks! :)

Mathematics
1 answer:
Leona [35]3 years ago
5 0
Um I think it is 1800
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What is 0.5, 1/5, 0.35, 12/25, 4/5 in order from least to greatest?
Aleks [24]
1/5, 0.35, 12/25, 0.5, 4/5
3 0
3 years ago
Read 2 more answers
Two factories I and II produce phones for brand ABC. Factory I produces 60% of all ABC phones, and factory II produces 40%. 10%
denpristay [2]

Answer:

0.3721 or 37.21%

Step-by-step explanation:

P(I) = 0.60; P(II) = 0.40;

P(not defective I) = 0.90; P(not defective II) = 0.80

The probability that the phone came from factory II, given that is not defective, is determined by the probability of a phone from factory II not being defective divided by the probability of a phone not being defective.

P(II|not) = \frac{P(II)*P(not_{II})}{P(II)*P(not_{II})+P(I)*P(not_{I})}\\P(II|not) = \frac{0.40*0.80}{0.40*0.80+0.60*0.90}\\ P(II|not) =0.3721 = 37.21\%

The probability is 0.3721 or 37.21%.

4 0
3 years ago
Let f(x) be a func. satisfying f(-x)=f(x) for all real x.if f"(x) exist, find its value.
OverLord2011 [107]

Answer:

f''(x)=f''(-x)

Step-by-step explanation:

A function satisfying the equation f(x)=f(-x) is said to be an even function. This denomination comes from the fact that the same relation is satisfied for functions of the form x^{n} with n even. Observe that if f is twice differentiable we can derivate using the chaing rule as follows:

f(x)=f(-x) implies f'(x)=f'(-x)\cdot (-1)=-f'(-x)

Applying the chain rule again we have:

f'(x)=-f'(-x) implies f''(x)=-f''(-x)\cdot (-1)=f''(-x)

So we have that function f''(x) is also an even function.

4 0
4 years ago
A square and a circle intersect so that each side of the square contains a chord of the circle equal in length to the radius of
krek1111 [17]

Answer:

Step-by-step explanation:

it is given that Square contains a chord of of the circle equal to the radius thus from diagram

QR=chord =radius =R

If Chord is equal to radius then triangle PQR is an equilateral Triangle

Thus QO=\frac{R}{2}=RO

In triangle PQO applying Pythagoras theorem

(PQ)^2=(PO)^2+(QO)^2

PO=\sqrt{(PQ)^2-(QO)^2}

PO=\sqrt{R^2-\frac{R^2}{4}}

PO=\frac{\sqrt{3}}{2}R

Thus length of Side of square =2PO=\sqrt{3}R

Area of square=(\sqrt{3}R)^2=3R^2

Area of Circle=\pi R^2

Ratio of square to the circle=\frac{3R^2}{\pi R^2}=\frac{3}{\pi }

5 0
3 years ago
Please help me i’m desperateeee!!!
lara31 [8.8K]

Answer:

option no.D

6y+15x

Step-by-step explanation:

hope it helps

7 0
3 years ago
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