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ra1l [238]
3 years ago
7

Identify the horizontal asymptote of each graph. t(x) = 67 y=0 y=1 y=6

Mathematics
2 answers:
zloy xaker [14]3 years ago
6 0

Answer:

First Graph (Shown above): A) y = 0

Second Graph: y = -3

pychu [463]3 years ago
3 0

Answer:

t(x) = 6^x.   First graph is y=0

t(x) = 5^x -3                  Second Graph is y= -3

Step-by-step explanation:

Correct on edge.

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prisoha [69]
B : 30
95+55 = 150
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6 0
3 years ago
What is the answer need it
denis-greek [22]

Answer:

\frac{7}{10} |

Step-by-step explanation:

STEP 1:

2/3 + 7/10 = ?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(2/3, 7/10) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(\frac{2}{3} * \frac{10}{10}) + (\frac{7}{10} * \frac{3}{3}) = ?

Complete the multiplication and the equation becomes

\frac{20}{30} + \frac{21}{30}

The two fractions now have like denominators so you can add the numerators.

Then:

\frac{20+21}{30} = \frac{41}{30}

This fraction cannot be reduced.

The fraction 41/30

is the same as

41 divided by 30

Convert to a mixed number using

long division for 41 ÷ 30 = 1R11, so

41/30 = 1 11/30

Therefore:

2/3+7/10= 1 11/30

STEP 2:

41/30 + -2/3

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(41/30, -2/3) = 30

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(\frac{41}{30} *\frac{1}{1} ) + ( \frac{-2}{3} * \frac{10}{10} )

The two fractions now have like denominators so you can add the numerators.

Then:

\frac{41+-20}{30} = \frac{21}{30}

This fraction can be reduced by dividing both the numerator and denominator by the Greatest Common Factor of 21 and 30 using

GCF(21,30) = 3

\frac{21/3}{30/3} =\frac{7}{10}

Therefore:

\frac{41}{30} + \frac{-2}{3} =\frac{7}{10}|

8 0
3 years ago
Hey can anyone pls help me in this real quick!!!!
Bas_tet [7]

Answer:

1.The Pythagorean theorem is used in football by telling the defender how much is necessary to run.For example the ball carrier is heading for the end zone 40 yards away.The defender stands 30 yards away and needs to defend him. Pythagorean theorem states A^2 +B^2=C^2.so comparing to Pythagorean theorem these sides are the legs of the triangle. forming 90 degree angle. The distance the defender need to run is the hypotenuse. So (40^2)times(30^2)=50^2.

2. It would be important for a football player to understand the Pythagorean theorem because that way they can now the direction there running, and angle defender needs to run, the speed need to use to outrun opponent, and so that the defender can now what distance to run in a the same time it takes the ball carrier to run to the same place. This can make a difference between a touchdown or a game saving tackle.

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4 0
4 years ago
What is the answer for the equation 4y + 3y + 2y =
max2010maxim [7]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Solve for x 14 x square+7x-6
irina [24]

Answer:

x=0.450765 or x=−0.950765

Step-by-step explanation:

14x² + 7x - 6

→ Find the product, sum and factors

Product = -6

Sum = 7

Factors = No factors

→ Since there are no factors utilise the quadratic formula

\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

→ List the values of a, b and c

a = 14

b = 7

c= -6

→ Substitute into the formula

\frac{-7+-\sqrt{7^{2}-4*14*-6} }{2*14}

→ Simplify

x=0.450765 or x=−0.950765

8 0
4 years ago
Read 2 more answers
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