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3 years ago

The missing number in the arithmetic sequence 60, 51, ___, 33 is:

Mathematics

1 answer:

andrew-mc [135]3 years ago

8 0

Answer:

Step-by-step explanation:

In this question, we have the find the rate of change in the sequence.

To find this, we need to find how much the sequence is changing by.

We know from 60 to 51 is -9, so we know that our sequence is changing by -9.

To find our unknown number, we would subtract 9 from 51.

51 - 9 = 42

Our missing number in the sequence is 42.

We can check our answer by subtracting 9 from 42. This gives us our next number, which is 33.

42 would be your answer.

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Answer:

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3 years ago

Solve for x and y <br> x+y=1<br> 2y-x=8

lara31 [8.8K]

Answer:

(- 2, 3 )

Step-by-step explanation:

Given the 2 equations

x + y = 1 → (1)

2y - x = 8 → (2)

Adding the 2 equations term by term will eliminate the x- term

(x - x) + (y + 2y) = (1 + 8), that is

3y = 9 ( divide both sides by 3 )

y = 3

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7 0

3 years ago

The mass of an electron is approximately 9 × 10-28 grams, while the mass of a neutron is approximately 2 × 10-24 grams. Which of

aalyn [17]

Answer: the mass of a neutron is approximately 2,000 times the mass of an electron

Step-by-step explanation:

- the easiest way to solve this (in my opinion) is to simply divide the mass of a neutron by the mass of an electron

- $2 x10^{-24} / (9 x10^{-28} )$

= $(2/9) x10^{-24--28}$

= $(2/9)x10^{-24+28}$

≈ $0.2222x10^{28-24}$

≈ $0.2222x10^{4}$

≈ which is approximately 2222

- so 2222 is approximately 2000 times

- therefore, the mass of a neutron is approximately 2,000 times the mass of an electron

hope this helps :)

4 0

2 years ago

Read 2 more answers

A rectangular poster is to contain 882 square inches of print. The margins at the top and bottom of the poster are to be 2 inche

Zinaida [17]

Answer:

L = 23 in

h = 46 in

Step-by-step explanation:

Let call " x " and " y " dimensions of the print area of the poster then:

882 = x*y and y = 882/x

We also know that dimensions of the poster is:

L = x + 2 in and h = y + 4 in

Therefore area of the poster is:

A(p) = ( x + 2 ) * ( y + 4 ) And area as function of x is:

A(x) = ( x + 2 ) * ( 882/x + 4 )

A(x) = 882 + 4*x + 1764 /x + 8

Taking derivatives on both sides of the equation we have:

A´(x) = 4 - 1764/x²

A´(x) = 0 ⇒ 4 - 1764/x² = 0 ⇒ 4*x² - 1764 = 0

x² = 1764 / 4

x² = 441

x = 21 in and y = 882/x y = 42

The second derivative A´´(x) is > 0 ( the second term changes its sign to +) there is a minimum for the function at the point x = 21

As x and y are dimensions of the printing area of the poster, dimensions of the poster are

L = x + 2 = 21 + 2 = 23 in and

h = y + 4 = 42 + 4 = 46 in

4 0

3 years ago