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3 years ago

The missing number in the arithmetic sequence 60, 51, ___, 33 is:

Mathematics

1 answer:

andrew-mc [135]3 years ago

8 0

Answer:

Step-by-step explanation:

In this question, we have the find the rate of change in the sequence.

To find this, we need to find how much the sequence is changing by.

We know from 60 to 51 is -9, so we know that our sequence is changing by -9.

To find our unknown number, we would subtract 9 from 51.

51 - 9 = 42

Our missing number in the sequence is 42.

We can check our answer by subtracting 9 from 42. This gives us our next number, which is 33.

42 would be your answer.

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Please help, me find the area of Letter E.

Radda [10]

Answer:

7.005 m^2.

Step-by-step explanation:

We can split this into one vertical rectangle 3.45 * 0.9 m^2

2 rectangles 2 * 0.75 = 1.5 m^2

1 rectangle 1.2 * 0.75 m^2

= 3.105 + 2 * 1.5 + 0.9

= 7.005 m^2.

7 0

3 years ago

If trapezoid JKLM is translated according to the rule (x,y)—> (x+2, y - 6), what are the coordinates of point L

guapka [62]

Answer:

( x, y) is translation '2' units right and '6' units down

(x ,y))—> (x +2 ,y-6)

Step-by-step explanation:

Explanation:-

Type of transformation change to co-ordinate point

vertical translation up 'd' units (x,y) changes to (x , y+d)

vertical translation down 'd' units (x,y) changes to (x , y-d)

Horizontal translation left 'c' units (x,y) changes to (x-c , y)

Horizontal translation right 'c' units (x,y) changes to (x+c , y)

Now by use above table

given data ( x, y) is translation '2' units right and '6' units down

(x ,y))—> (x +2 ,y-6)

Final answer:-

( x, y) is translation '2' units right and '6' units down

(x ,y))—> (x +2 ,y-6)

3 0

3 years ago

A scientest is studying a new super bacteria that is threatening to cause an outbreak. On the first day, there were 5 organisms

ElenaW [278]

Answer:

C. 125

Step-by-step explanation:

Given:

Bacteria on day 1 = 5

On day 2, each bacteria got split into 5.

So, number of bacteria on day 2 = $5\times 5 = 25$

Now, again on day 3, each of the 25 bacteria got split into additional 5 bacteria.

So, number of of bacteria on day 3 = $25\times 5 =125$

Therefore, the population of bacteria on day 3 is 125.

8 0

2 years ago

After responding to a distress call from the planet Xudar in space sector 2813, a group of Green Lanterns spot 6 suspected crimi

Olin [163]

Answer:

10000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%

Step-by-step explanation:

100%

5 0

3 years ago

The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in fourth quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in 4th quadrant so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

6 0

2 years ago