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bearhunter [10]
2 years ago
12

Under the proper conditions, bromomethane (ch3br) will react with potassium hydroxide (koh) to form _____ and a salt. methanol (

ch3oh) methane (ch4) bromoethane (ch3ch2br) ethanol (ch3ch2oh)
Chemistry
2 answers:
mihalych1998 [28]2 years ago
8 0
The first option is the answer ... methanol.
Luden [163]2 years ago
7 0
Methanol (ch3oh) i believe.
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The compound Fe2O3 contains how many atoms? <br> A) 2 <br> B) 3 <br> C) 5 <br> D) 7
marishachu [46]
The compound Fe2O3 contains C) 5 total atoms.

This is because there are 2 atoms of Fe (iron) and 3 atoms of O (oxygen) bonded together in this compound, as denoted by the subscripts, and 2+3 = 5.

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4 0
3 years ago
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Provide an explanation that is grounded in polarity that better explains why oil is not miscible in vinegar.
butalik [34]

Explanation:

Vinegar is a sour liquid made up of acetic acid compounds. Oil is a complex non-polar chemical compound with a high amount of hydrogen and carbon in its structure.

  • Vinegar is a polar acid, although a weak one.
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Learn more:

Polarity brainly.com/question/2615067

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4 0
2 years ago
Sulfuric acid dissolves and completely dissociates in water and a solvation sphere of water molecules forms around the ions. Thi
Elan Coil [88]

This solute-solvent interaction will release energy into the surroundings and makes the beaker warm.

<u>Explanation:</u>

The sulfuric acid is dissolved in water and it formed a solvation sphere of water molecules around the sulphur ions. So on stirring the beaker is getting warm. As the beaker is getting warm, this means the reaction occuring between sulfuric acid and water is exothermic reaction.

And so the energy is released into the surroundings. The energy released came from the breaking of bonds of sulfuric acid, as the acid is getting dissociated in water.

So, the release of energy in the surroundings lead to the warming of the beaker. Hence, the solute-solvent interaction release energy into the surroundings.

3 0
3 years ago
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Three people made the
mojhsa [17]

Answer:

the answer is b hope it helped

Explanation:

8 0
2 years ago
If the volume of wet gas collected over water is 85.0 mL at 20°C and 760 mm Hg , what is the volume of dry gas at STP conditions
dimulka [17.4K]

Answer: 77.4 mL

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of dry gas = (760 - 17.5) mmHg= 742.5 mm Hg

P_2 = final pressure of dry gas at STP =  760 mm Hg

V_1 = initial volume of dry gas = 85.0 mL

V_2 = final volume of dry gas at STP = ?

T_1 = initial temperature of dry gas = 20^oC=273+20=293K

T_2 = final temperature of dry gas at STP = 0^oC=273+0=273K

Now put all the given values in the above equation, we get the final volume of wet gas at STP

\frac{742.5mmHg\times 85.0ml}{293K}=\frac{760mmHg\times V_2}{273K}

V_2=77.4mL

Volume of dry gas at STP is 77.4 mL.

5 0
3 years ago
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