Answer:
involuntary, attached to the eyeball, nonstriated.
Explanation:
Answer:
Rutherford's experiment, also known as

supports the existence of neutrons and the nucleus.
Explanation:
In the above diagram, Rutherford was trying to explain his contributions using thin foils of gold and other metals as targets for alpha particles from a radioactive source.
He observed that the majority of particles penetrated the foil either undeflected or with only a slight deflection. But, every now and then an alpha particle was scattered(or deflected) at a large angle..
According to Rutherford, most of the atoms must be empty space. This explains why the majority of alpha particles passed through through the gold foil with little or no deflection. The atoms positive charges, Rutherford proposed are all concentrated in the Nucleus, <em>which</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>dense</em><em> </em><em>central</em><em> </em><em>core</em><em> </em><em>withi</em><em>n</em><em> </em><em>the</em><em> </em><em>atom</em><em>. </em>
Whenever an alpha particle came close to a nucleus in the scattering experiment, it experienced a large repulsive force and therefore a large deflection. Moreover, an alpha particle coming towards a nucleus would be completely repelled and its direction would be reversed. The positively charged particles in the Nucleus are called Protons.
I <em>hope</em><em> </em><em>you</em><em> </em><em>find</em><em> </em><em>this</em><em> </em><em>useful</em><em>.</em><em>.</em><em>. </em><em>Have</em><em> </em><em>a</em><em> </em><em>lovely</em><em> </em><em>day</em><em>. </em>
it is water energy :) this is easy
Answer:
i) CCl₄ and Br₂ does not react
ii) CBr₄ + Cl₂ → CCl₄ + Br₂
Explanation:
i) CCl₄ + Br₂ (no reaction)
From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CCl₄ + Br₂ will not have a reaction as the propensity for the chlorine to stay combined with the carbon is higher than the ability for bromine to remain combined with or attract the carbon. Therefore, for CCl₄ + Br₂ there is no reaction
ii) CBr₄ + Cl₂
From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CBr₄ + Cl₂ will give products that will have the Br in the CBr₄ replaced by the Cl₂ as follows;
CBr₄ + Cl₂ → CCl₄ + Br₂
The products of the reaction of CBr₄ and Cl₂ are therefore CBr₄ and Cl₂.