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Y_Kistochka [10]
3 years ago
11

Which organism obtains energy without depending on another organism

Chemistry
1 answer:
DanielleElmas [232]3 years ago
4 0

Answer:

Plants

Explanation:

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Is cornstarch able to disintegrate in fire or an open flame?
Darya [45]

Answer:

Yes

Explanation:

I just quickly looked it up. Cornstarch is extremely flammable.

7 0
2 years ago
Read 2 more answers
Please help thaank youu
krek1111 [17]
First, let's start off by finding the mass of this whole hydrate.
(Note: the unit of measurement for mass will be amu)

Let's find the molecular mass of each element.
Co=58.933
Cl=35.45
H=1.008
O=15.999

Now, let's find the mass of each compound.

CoCl_2=58.933+2(35.45)=129.833
H_2O=2(1.008)+15.999=18.015

We have 6 molecules of H2O, so multiply 18.015 by 6 then add that with the weight of CoCl2.

6(18.015)=108.09
129.833+108.09=237.923

Now divide 108.09 (mass of all the H2O in the hydrate) by 237.923 (total mass of hydrate).

\dfrac{108.09}{237.923}

\approx0.45431

Turn that into a percentage and you get 45.431%.
Hope this helps! :)
6 0
3 years ago
Calculate the mass of Cr(ClO2)2 that contains 5.57 × 10<br> ^22 chlorine atoms.
Anna007 [38]

Answer:

Explanation:

Your strategy here will be to

use the chemical formula of carbon dioxide to find the number of molecules of

CO

2

that would contain that many atoms of oxygen

use Avogadro's constant to convert the number of molecules to moles of carbon dioxide

use the molar mass of carbon dioxide to convert the moles to grams

So, you know that one molecule of carbon dioxide contains

one atom of carbon,

1

×

C

two atoms of oxygen,

2

×

O

This means that the given number of atoms of oxygen would correspond to

4.8

⋅

10

22

atoms O

⋅

1 molecule CO

2

2

atoms O

=

2.4

⋅

10

22

molecules CO

2

Now, one mole of any molecular substance contains exactly

6.022

⋅

10

22

molecules of that substance -- this is known as Avogadro's constant.

In your case, the sample of carbon dioxide molecules contains

2.4

⋅

10

22

molecules CO

2

⋅

1 mole CO

2

6.022

⋅

10

23

molecules CO

2

=

0.03985 moles CO

2

Finally, carbon dioxide has a molar mass of

44.01 g mol

−

1

, which means that your sample will have a mass of

0.03985

moles CO

2

⋅

44.01 g

1

mole CO

2

=

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

∣

∣

a

a

1.8 g

a

a

∣

∣

−−−−−−−−−

The answer is rounded to two sig figs, the number of sig figs you have for the number of atoms of oxygen present in the sample.

3 0
2 years ago
Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Svet_ta [14]

Answer:

V_1=23.3~mL

Explanation:

In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:

C_1*V_1=C_2*V_2

Now we can identify the variables:

C_1=~1.475_M

V_1=~?

C_2=~0.1374_M

V_2=~250.0~mL

If we plug all the values into the equation:

1.475_M*V_1=0.1374_M*250.0~mL

And we solve for V_1:

V_1=\frac{0.1374_M*250.0~mL}{1.475_M}

V_1=23.3~mL

I hope it helps!

8 0
3 years ago
Help mee please (I will give the person who answers this a brainlist)
Leokris [45]
2 5 3 4 1 is the answers
7 0
3 years ago
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