Answer:
// here is code in c++.
#include <bits/stdc++.h>
using namespace std;
// main function
int main() {
// variable
int num;
int tot_sum=0;
cout<<"enter a number: ";
// read the value of n
cin>>num;
// check the multiple of 2 or 5 from 1 to n
for(int x=1;x<=num;x++)
{
// if multiple of 2 or 5 then add them
if(x%2==0 ||x%5==0)
{
tot_sum=tot_sum+x;
}
}
// print the sum
cout<<"sum of multiple of 2 or 5 is:"<<tot_sum<<endl;
return 0;
}
Explanation:
Read the number "n" from user.Check every number from 1 to n, if it is a multiple of 2 or 5 then add them to "tot_sum".When the for loop end, "tot_sum" will have sum of all the number which are either multiple of 2 or 5.Print the sum.
Output:
enter a number:11
sum of multiple of 2 or 5 is:35
Answer:
<em>C++</em>
////////////////////////////////////////////////////////////////////////////////////////////////////////
#include <iostream>
#include <vector>
using namespace std;
int main() {
vector<int> v;
int n = 1;
while (n != 0) {
cout<<"Enter an integer, the input ends if it is 0: ";
cin>>n;
v.push_back(n);
}
cout<<endl;
///////////////////////////////////////////////////////////
int sum = 0;
int num_positives = 0, num_negatives = 0;
for (int i=0; i<v.size()-1; i++) {
if (v[i] > 0)
++num_positives;
else
++num_negatives;
sum = sum + v[i];
}
//////////////////////////////////////////////////////////
cout<<"The number of positives is "<<num_positives<<endl;
cout<<"The number of negatives is "<<num_negatives<<endl;
cout<<"The total is "<<sum<<endl;
cout<<"The average is "<<(float)sum/(v.size()-1);
///////////////////////////////////////////////////////////
return 0;
}
Answer:b) Mail settings can be changed under the options menu
Explanation: I fr just guessed so y’all can have an answer and I ended up getting it rights
False.
The different between break and continue instruction is that with break you exit the loop, and with continue you skip to the next iteration.
So, for example, a loop like
for(i = 1; i <= 10; i++){
if(i <= 5){
print(i);
} else {
break;
}
}
will print 1,2,3,4,5, because when i=6 you will enter the else branch and you will exit the loop because of the break instruction.
On the other hand, a loop like
for(i = 1; i <= 10; i++){
if(i % 2 == 0){
print(i);
} else {
continue;
}
}
Will print 2,4,6,8,10, because if i is even you print it, and if i is odd you will simply skip to the next iteration.
Answer: Answer below.
Explanation:
I'm not fully sure myself, so don't agree with me fully.
I believe what she may have done wrong is tell the technician about a "program." A program doesn't have to do anything with physical hardware.
