Answer:
Blue
Explanation:
set_Property - (topButton), (#background-color), (orange)
set_Property - (bottomButton), (#background-color), (red)
set_Property - (topButton), (#background-color), (blue)
set_Property - (bottomButton), (#background-color), (green)
Here, the background color for the 'topButton' would be "blue" when the program is finished running, as it is the last task, the topButton would be set to or it is the last thing that will run for the button.
Answer:
#include <iostream>
#include <map>
using namespace std;
int main()
{
map<int, int> numbers;
cout << "Enter numbers, 0 to finish" << endl;
int number;
while (true) {
cin >> number;
if (number == 0) break;
numbers[number]++;
}
for (pair<int, int> element : numbers) {
std::cout << element.first << ": occurs " << element.second << " times" << std::endl;
}
}
Explanation:
One trick used here is not to keep track of the numbers themselves (since that is not a requirement), but start counting their occurrances right away. An STL map< > is a more suitable construct than a vector< >.
Answer:
Explanation:
a. In this scenario, the best solution would have an Object of Traditional Books, CD, Music, Bookstore and Customer.
b. All five objects would be able to be called by the main program loop and the Customer Object would call upon and use either the Books or CD object, While the Bookstore object would call upon all of the other objects.
c. Both the Bookstore object and Customer object will "have" other objects as the Bookstore needs to hold information on every Book or CD in the Inventory. While the Customer object would call upon the Book and CD object that they are purchasing.
d. The Music Object will extend the CD object and use information on the CD object as its parent class.
e. Since the Music Object extends the CD object it is also considered a CD since it is in CD format like the Books on CD and therefore is both objects.
