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shutvik [7]
3 years ago
8

may runs 10/4 miles everyday after school. Beth says that she runs farther than May every day because she runs 5/2 miles everyda

y after school. is her statement correct
Mathematics
1 answer:
Degger [83]3 years ago
5 0
Yes her statement is correct i think well maybe it is because if you cut 3 rectangles in to 2 than you color in 5 and stop and draw a rectangle with 4 in 3 rectangles and color in 10 and the two has less shaded in so the one who ran more was beth cause if you put it into a mixed number it is 2 and 1/2 and May's mixed number is 2 and 2/4 and the dinominator 2 is greater than the dinominator 4 cause 2 has bigger pices and 4 has smaller pices
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The sum of two numbers exceeds their product by one.Their difference is equal to their products less five .Find the two numbers
Ludmilka [50]

Answer:

1 and 3

Step-by-step explanation:

If the two numbers are x and y, then:

x + y = xy + 1

x − y = xy − 5

Subtract the two equations:

(x + y) − (x − y) = (xy + 1) − (xy − 5)

x + y − x + y = xy + 1 − xy + 5

2y = 6

y = 3

Solve for x:

x + 3 = 3x + 1

2 = 2x

x = 1

The numbers are 1 and 3.

4 0
3 years ago
Warm-Up<br> What is the<br> X<br> 10<br> х<br> 8<br> 00
Kryger [21]
Um. It might be 100. I do not now. Sorry
5 0
2 years ago
Find three points of the linear equation -x-2y=-10
n200080 [17]
We can find 3 points by plugging them in

x = -12 y = 1
x = 10 y = 0
x = 0 y = 5
6 0
4 years ago
9) Out of the 15 friends that I have, the
tino4ka555 [31]

The answer is b because the ratio is blondes to brunettes.

5 0
4 years ago
Given the following matrices, what 3 elements make up the first column of the product matrix DA?
Misha Larkins [42]

We have to figure out what the product of DA is,

\begin{bmatrix}-1&2&3\\8&-4&0\\6&7&1\\ \end{bmatrix}\begin{bmatrix}1\\3\\5\\ \end{bmatrix}=\begin{bmatrix}a\\b\\c\\ \end{bmatrix}

We know that,

\begin{bmatrix}a&b&c\\d&e&f\\g&h&i\\\end{bmatrix}\begin{bmatrix}x\\y\\z\\\end{bmatrix}=\begin{bmatrix}ax+by+cz\\dx+ey+fz\\gx+hy+iz\\\end{bmatrix}

So,

a=-1\cdot1+2\cdot3+3\cdot5=-1+6+15=20

b=8\cdot1+(-4)\cdot3+0\cdot5=8-12=-4

c=6\cdot1+7\cdot3+1\cdot5=6+21+5=32

So the solution is,

a,b,c=\boxed{20,-4,32}

Hope this helps :)

4 0
3 years ago
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