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3 years ago

Highest common factor of 170 and 238

Mathematics

1 answer:

irakobra [83]3 years ago

7 0

Answer:

The GCF is 34

Step-by-step explanation:

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How do I set up the equation for this word problem? A takes 1/2 of the diamonds plus 1 from the table. B takes 2/3 of what remai

nalin [4]

The first thief takes (1/2 x + 1) . What remains ? x - (1/2x + 1)

So the 2nd thief takes 2/3 of [ x - (1/2x + 1) ]

What remains ? x - 2/3 [ x - (1/2x + 1) ]

So the 3rd thief takes 2/3 of { x - 2/3 [ x - (1/2x + 1) ] } and he takes 1 more .

What remains ? x - ( 2/3 { x - 2/3 [ x - (1/2x + 1) ] } + 1 )

And that whole ugly thing is equal to ' 1 ', so you can solve it for 'x'..

The whole problem from here on is an exercise in simplifying
an expression with a bunch of 'nested' parentheses in it.
===============================================
This is a lot harder than just solving the problem with logic and
waving your hands in the air. Here's how you would do that:

Start from the end and work backwards:

-- One diamond is left.
-- Before the 3rd thief took 1 more, there were 2.
-- That was 1/3 of what was there before the 3rd man took 2/3.
So he found 6 when he arrived.
-- 6 was 1/3 of what was there before the second thief helped himself.
So there were 18 when the 2nd man arrived.
-- 18 was 1 less than what was there before the first thief took 1 extra.
So he took his 1 extra from 19.
-- 19 was the remaining after the first man took 1/2 of all on the table.
So there were 38 on the table when he arrived.

Thank you for your generous 5 points.

3 0

3 years ago

Finding values or<br> k(x) = x - 2<br> h(x) = x2 +1<br> (h + k)(2) =

Serjik [45]

Answer:

Step-by-step explanation:

$(h+k)(x)=h(x)+k(x)\\\\\bold{METHOD\ 1:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(k+h)(2)=h(2)+k(2)\\\\\text{Calculate}\ h(2)\ \text{and}\ k(2).\\\text{Put}\ x=2\ \text{to the equations of the functions}\\\\h(2)=2^2+1=4+1=5\\k(2)=2-2=0\\\\\text\\\\\text{Substitute:}\\\\(h+k)(2)=5+0=5$

$\bold{METHOD\ 2:}\\\\k(x)=x-2,\ h(x)=x^2+1\\\\(h+k)(x)=h(x)+k(x)=(x^2+1)+(x-2)=x^2+x-1\\\\(h+k)(2)-\text{put}\ x=2\\\\(h+k)(2)=2^2+2-1=4+2-1=6-1=5$

5 0

3 years ago

Help me solve for x ?

Ksenya-84 [330]

Answer:

Step-by-step explanation:

8 0

2 years ago

13) -4= -b -1/3b and -23/3= 1/2a + 5/3a

Sergeeva-Olga [200]

-4=-1b-(1/3)b

-4=-(4/3)b

-4/-(4/3)=b

b=3

-------------------------------

(1/2)3+(5/3)2

3/6+10/6=13/6

-23/3=13/6a

(-23/3)/(13/6)=a

a=-46/13

7 0

3 years ago

For this set of data,<br> 89, 88, 84, 87, 89, 84, 84, 83, 85, 89, 84<br> Find the standard deviation

Ilia_Sergeevich [38]

Answer: 2.2962419891482

Step-by-step explanation: First get the mean of the numbers or the average

the mean in this case is 86

then subtract each number by the mean of 86

the numbers then become : 3, 2, -2, 1, 3, -2, -2, -3, -1, 3, -2

then square all the numbers to get : 9, 4, 4, 1, 9, 4, -4, 9, 1, 9, 4

then find the mean of those numbers which is 5.2727272727273

then find the square root of this number to find the standard deviation

2.2962419891482 is the standard deviation

hope this helps mark me brainliest if it helped

6 0

3 years ago