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STALIN [3.7K]
2 years ago
12

Highest common factor of 170 and 238

Mathematics
1 answer:
irakobra [83]2 years ago
7 0

Answer:

The GCF is 34

Step-by-step explanation:


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For every 144 light bulbs produced, 6 are defective. Find the number of defective light bulbs that could be expected out of 720.
Lelu [443]
You are going to get the rate of the detects.
6 detects ÷ 114 light bulbs = 1/19 detects per light bulb

If there are 720 light bulbs, then the number of detects will be
720 light bulbs * 1/19 detects per light bulb = 37. 89 ≈ 38 detects
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3 years ago
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Which ordered pair is a solution of this<br> equation?<br> -3x + 7y - 6<br> =
Mumz [18]

Answer:

There are actually an infinite number of ordered pairs that will satisfy the equation y=3x+7 including (-1,4), (0,7) and (1, 10).

Step-by-step explanation:

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2 years ago
What is the simplified form of the following expression?
geniusboy [140]

Answer:

242

Step-by-step explanation:

Simplify the following:

11 ((9^2 - 5^2)/2^2 + 8)

Hint: | Evaluate 2^2.

2^2 = 4:

11 ((9^2 - 5^2)/4 + 8)

Hint: | Evaluate 5^2.

5^2 = 25:

11 ((9^2 - 25)/4 + 8)

Hint: | Evaluate 9^2.

9^2 = 81:

11 ((81 - 25)/4 + 8)

Hint: | Subtract 25 from 81.

| 7 | 11

| 8 | 1

- | 2 | 5

| 5 | 6:

11 (56/4 + 8)

Hint: | Reduce 56/4 to lowest terms. Start by finding the GCD of 56 and 4.

The gcd of 56 and 4 is 4, so 56/4 = (4×14)/(4×1) = 4/4×14 = 14:

11 (14 + 8)

Hint: | Evaluate 14 + 8 using long addition.

| 1 |  

| 1 | 4

+ | | 8

| 2 | 2:

11×22

Hint: | Multiply 11 and 22 together.

| 2 | 2

× | 1 | 1

| 2 | 2

2 | 2 | 0

2 | 4 | 2:

Answer: 242

3 0
2 years ago
P(A) = ? <br> Explain how you got the answer as well.
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Answer:

0.5

Step-by-step explanation:

we see that A is 1 of 2 choices, so theoretically, P(A) = 1/2 = 0.5

5 0
3 years ago
You want to put $2,000 in a simple intrest account.It has a 2.5% annual interest rate.How long will it take you to earn $500 in
PSYCHO15rus [73]
The answer is C ten years. 2.5 percent of 2000 is 50 so take 50 and divide it by 500 which equals 10
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3 years ago
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