Answer:
<u>x = 5</u>
Step-by-step explanation:
See attached image.
soln,
here area of base = 25/4 unit ^ 2
height of the prism = 8/5 unit
so,
volume of prism = area of base x height of the prism
so the volume of the prism is 10 unit^2
4.5 is the answer
Divide 49 from both sides
220.5 / 49 = 4.5
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
25.12 in^3.
Step-by-step explanation:
Volume of the cylinder = 3.14 * r^2 * h
= 3.14 * 2^2 * 8
The volume of the preserve
= 1/4 * 3.14 * 4 * 8
= 25.12 in^3.
