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2 years ago

X=3G/2 rearrange to make g the subject

Mathematics

2 answers:

Alexandra [31]2 years ago

6 0

2x/3=g I think I’m not fully sure

andre [41]2 years ago

4 0

Answer:

2x/3 = G

Step-by-step explanation:

X=3G/2

2X= 3G

2X/3 = G

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What is the length of the midsegment of the trapezoid

makkiz [27]

Answer:

The length of the mid-segment of the trapezoid = 7

==================================================

Step-by-step explanation:

The mid-segment of a trapezoid is the segment that connecting the midpoints of the two non-parallel sides.

As shown in the figure the two non-parallel sides are AB and CD

∴ The mid-segment of the trapezoid = $\frac{BC +AD}{2}$

From the figure: BC = 8 and AD = 6

∴ The mid-segment of the trapezoid = $\frac{8+6}{2} = 7$

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3 years ago

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Alecsey [184]

Answer:

Step-by-step explanation:

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3 years ago

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Andre45 [30]

Answer:

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2 years ago

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The line x = k intersects the graph of the parabola x = -2y^2 - 3y + 5 at exactly one point. What is k? Thank you! :)

bearhunter [10]

Answer:

49/8 is the value of k

Step-by-step explanation:

We have the system

x = -2y^2 - 3y + 5

x=k

We want to find k such that the system intersects once.

If we substitute the second into the first giving us k=-2y^2-3y+5 we should see we have a quadratic equation in terms of variable y.

This equation has one solution when it's discriminant is 0.

Let's first rewrite the equation in standard form.

Subtracting k on both sides gives

0=-2y^2-3y+5-k

The discriminant can be found by evaluating

b^2-4ac.

Upon comparing 0=-2y^2-3y+5-k to 0=ax^2+bx+c, we see that

a=-2, b=-3, and c=5-k.

So we want to solve the following equation for k:

(-3)^2-4(-2)(5-k)=0

9+8(5-k)=0

Distribute:

9+40-8k=0

49-8k=0

Add 8k on both sides:

49=8k

Divide both sides by 8"

49/8=k

6 0

3 years ago

Below is the five-number summary for 144 hikers who recently completed the John Muir Trail (JMT). The variable is the amount of

bearhunter [10]

Answer:

The IQR is given by:

$IQR = Q_3 -Q_1 = 28-18= 10$

If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

$Upper= Q_3 + 1.5 IQR$

And if we find the lower limt we got:

$Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3$

$Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43$

So then the left boundary for this case would be 3 days

Step-by-step explanation:

For this case we have the following 5 number summary from the data of 144 values:

Minimum: 9 days

Q1: 18 days

Median: 21 days

Q3: 28 days

Maximum: 56 days

The IQR is given by:

$IQR = Q_3 -Q_1 = 28-18= 10$

If we want to find any possible outliers we can use the following formulas for the limits:

$Lower= Q_1 - 1.5 IQR$

$Upper= Q_3 + 1.5 IQR$

And if we find the lower limt we got:

$Lower= Q_1 - 1.5 IQR= 18-1.5*10 = 3$

$Upper= Q_3 + 1.5 IQR= 28+1.5*10= 43$

So then the left boundary for this case would be 3 days

6 0

3 years ago