Answer:
Use the formula
g = GM/R^2
where
g = acceleration of gravity on moon
G = universal gravitational constant
= 6.67 x 10^-11 m^3/kg-s^2
M = mass of the moon
R = radius of the moon
solving for R, we get
R = 1.74 x 10^6 kg
Answer:
a what
well it wouldn't matter because it's not counted a planet anyway
Explanation:
Answer:
Explanation:
Force on q due to Q
= k Qq / ( a² + d²)
x component
= k Qq / ( a² + d²) x d /√ ( a² + d²)
F = kQq d/ ( a² + d²)³/²
differentiating F with respect to d
dF / Dd = kQq [ d. -3/2 ( a² + d²)⁻⁵/² 2d + ( a² + d²)⁻³/²]=0 for maximum F
- 3d² / ( a² + d²) + 1 = 0
a² + d² = 3 d²
a² = 2d²
d = a / √2
The gravitational force is 1.98×10^20 m.
Computation of gravitational force:
The gravitational force F between two masses is given by the formula,
F=Gm1m2/ r^2
where G is the gravitational constant.
Note: It is assumed m1=5.972×10^24 kg, m2=7.348×10^22 kg and r=3.84×10^8 m and G=6.67×10^(-11) N m^2 kg^-2
Then F=(6.67×10^(-11)×5.972×10^(24)×7.348×10^(22))/ (3.84×10^8)
F=1.98×10^(20) N
Check out more about gravitational force here:
brainly.com/question/13054973
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