Answer:
if this is a true or false question then it is true.
Explanation:
Lower mass: 1.20 kg, upper mass: 1.28 kg
Explanation:
In order to solve the problem, we consider the forces acting on the upper mass only first.
The upper mass is acted upon three forces:
- The applied force
, upward - The weight of the mass itself,
, where
is the upper mass and
is the acceleration of gravity, downward - The tension in the string,
, downward
Therefore, the equation of the forces for the upper mass is:

where
is the acceleration (upward)
Solving for
,

Now we can find the lower mass by considering the forces acting on it:
- The tension in the string, T = 16 N, upward
- The weight of the mass itself,
, where
is the lower mass, downward
So the equation of the forces is

And solving for the mass,

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Answer:
691.13 nm
Explanation:
d = width of the slit = 0.11 x 10⁻³ m
θ = angle of diffraction pattern = 0.72° degree
λ = wavelength of the light = ?
m = order = 2 (since second minimum)
for the second minimum diffraction pattern we use the equation
d Sinθ = m λ
Inserting the values
(0.11 x 10⁻³) Sin0.72 = (2) λ
λ = 691.13 x 10⁻⁹ m
λ = 691.13 nm