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tia_tia [17]
3 years ago
5

Pls Help

Physics
1 answer:
QveST [7]3 years ago
8 0

Answer:

Use the formula

g = GM/R^2

where

g = acceleration of gravity on moon

G = universal gravitational constant

= 6.67 x 10^-11 m^3/kg-s^2

M = mass of the moon

R = radius of the moon

solving for R, we get

R = 1.74 x 10^6 kg

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Two masses are joined by a mass less string. A 33-N force applied vertically to the upper mass gives the system a constant upwar
lisov135 [29]

Lower mass: 1.20 kg, upper mass: 1.28 kg

Explanation:

In order to solve the problem, we consider the forces acting on the upper mass only first.

The upper mass is acted upon three forces:

  • The applied force F_a=33 N, upward
  • The weight of the mass itself, m_u g, where m_u is the upper mass and g=9.8 m/s^2 is the acceleration of gravity, downward
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Therefore, the equation of the forces for the upper mass is:

F_a - m_u g - T = m_u a

where

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Solving for m_u,

m_u = \frac{F_a-T}{a+g}=\frac{33-16}{3.5+9.8}=1.28 kg

Now we can find the lower mass by considering the forces acting on it:

  • The tension in the string, T = 16 N, upward
  • The weight of the mass itself, m_L g, where m_L is the lower mass, downward

So the equation of the forces is

T-m_L g = m_L a

And solving for the mass,

m_L = \frac{T}{a+g}=\frac{16}{3.5+9.8}=1.20 kg

Learn more about acceleration and forces:

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Read 2 more answers
The second minimum in the diffraction pattern of a 0.11-mm-wide slit occurs at 0.72°. What is the wavelength of the light?
Anit [1.1K]

Answer:

691.13 nm

Explanation:

d = width of the slit = 0.11 x 10⁻³ m

θ = angle of diffraction pattern = 0.72° degree

λ = wavelength of the light = ?

m = order = 2                              (since second minimum)

for the second minimum diffraction pattern we use the equation

d Sinθ = m λ

Inserting the values

(0.11 x 10⁻³) Sin0.72 = (2) λ

λ = 691.13 x 10⁻⁹ m

λ = 691.13 nm

6 0
3 years ago
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