All categories

3 years ago

Please explain how to solve it!!!

Physics

1 answer:

Alexxandr [17]3 years ago

6 0

All you need to do is to convert the velocity to meters per hour. Then multiply by 0.4 hours. I guess the answer was rounded up.

You might be interested in

Help me pls, the lesson is simple machines

Y_Kistochka [10]

Answer:

1.pulley,screw,inclined plane

2.using simple machine properly with right way and precautions

Explanation:

3.cuz if they are not used properly they can cause injuries to organs

8 0

2 years ago

What does the slope of the curve on a distance vs time graph represent?

Lilit [14]

Slope of a curve Y plotted against X is mathematically given as

$slope = \frac{dy}{dx}$

now here we can see that if similarly graph is plotted against distance and time then slope is given as

$slope = \frac{dx}{dt}$

here we can say that above is ratio of small distance and very small interval of time.

so here we can say that this ratio of distance and time for very small interval of time is known as instantaneous speed of the object which is falling freely under gravity.

So here slope of the graph will represent the speed at a given instant.

6 0

3 years ago

A 1420-kg car is traveling with a speed of 12.4 m/s. What is the magnitude of the horizontal net force that is required to bring

zzz [600]

Answer:

1419.01436 N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-12.4^2}{2\times 78}\\\Rightarrow a=-0.98564\ m/s^2$

The force on the car

$F=ma\\\Rightarrow F=1420\times -0.98564\\\Rightarrow F=-1419.01436\ N$

Magnitude of the horizontal net force that is required to bring the car to a halt is 1419.01436 N

3 0

3 years ago

Read 2 more answers

I DO NOT WANT LINKES OR …………..

il63 [147K]

1st B is correct option

2nd D is correct option

4 0

3 years ago

Read 2 more answers

Satellite A orbits the earth at a height 3.00 times the earth's radius. Satellite B orbits the earth at a height 2.00 times the

dsp73

The correct answer to this question is this one: "B) 1 to 3√(3/2)^2 "

The fact that Satellite A orbits the earth at a height 3.00 times the earth's radius and Satellite B orbits the earth at a height 2.00 times the earth's radius. The ratio of the of the period of Satellite B to the period of Satellite A is 1 : 3√(3/2)^2

7 0

4 years ago

Read 2 more answers