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earnstyle [38]
3 years ago
14

Please explain how to solve it!!!

Physics
1 answer:
Alexxandr [17]3 years ago
6 0
All you need to do is to convert the velocity to meters per hour. Then multiply by 0.4 hours. I guess the answer was rounded up.
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What mass of steam at 100°C must be mixed with 119 g of ice at its melting point, in a thermally insulated container, to produce
N76 [4]

Answer:M=27.92\ gm

Explanation:

Given

mass of ice m=119\ gm

Final temperature of liquid T_f=57^{\circ}C

Specific heat of water c=4186\ J/kg-K

Latent heat of fusion L=333\ kJ/kg

Latent heat of vaporization L_v=2256\ kJ/kg

Suppose M is the mass of steam at 100^{\circ} C

Heat required to melt ice and convert it to water at 57^{\circ}C

Q_1=mL+mc(T_f-0)

Heat released by steam

Q_2=ML_v+Mc(100-T_f)

Q_1 and Q_2 must be equal as the heat gained by ice is equal to Heat released by steam

Q_1=Q_2

\Rightarrow mL+mc(T_f-0)= ML_v+Mc(100-T_f)

\Rightarrow M=\dfrac{m[L+c\times T_f]}{L_v+c(100-T_f)}

\Rightarrow M=\dfrac{119[333\times 10^3+4186\times 57]}{2256\times 10^3+4186\times (100-57)}

\Rightarrow M=119\times 0.2346

M=27.92\ gm

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