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zysi [14]
3 years ago
7

An object moves along the x axis according to the equation x = 3.00t^2 - 2.00t + 3.00 where x is in meters and t is in seconds.

Physics
2 answers:
Nastasia [14]3 years ago
8 0
                                   x = 3 t²  -  2 t  +  3

When t=2 sec,          x = 3 (4) - 2 (2) + 3
                                     =  12    -   4     + 3  =  11 meters .

When t=3 sec,          x = 3 (9) - 2 (3) + 3
                                     =   27   -   6    +  3  =  24 meters .

Distance = (end position) - (start position) = (24m - 11m) = 13 meters  

Time  =  (end time) - (start time) = (3s - 2s)  =  1 second

Speed  =  (distance) / (time)  =  13 meters / 1 sec  =  13 meters/second
MakcuM [25]3 years ago
7 0
  We are given the equation:

x = 3 t²  -  2 t  +  3
We use that equation to calculate for the distance traveled.

At t=2 sec,          x = 3 (4) - 2 (2) + 3
                             x =11 meters

At t=3 sec,          x = 3 (9) - 2 (3) + 3
                             x = 24 meters

Velocity = (24 meters - <span>11 meters) / (3 s - 2 s )  = 13 m/s</span>
 
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If an object has a mass of 10 kilograms, how much does it weigh in newtons?
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4 years ago
the winner of a 10km road race took half an hour to complete the race. Calculate the average speed. Give your answer in metres p
leonid [27]
Hello there!

For this:

1). Convert 10km to meters!
2). Convert the 30 minutes into seconds!

3). Use the following formula to solve for speed!

speed= distance/time

Note: The units should automatically work out to m/s. :)

My goal is to make sure you understand the problem, which is why I won't be giving you the answer. It'll be more work now, but less work in the future! :)

Hope this helped!

-------------


DISCLAIMER: I am not a professional tutor or have any professional background in your subject. Please do not copy my work down, as that will only make things harder for you in the long run. Take the time to really understand this, and it'll make future problems easier. I am human, and may make mistakes, despite my best efforts. Again, I possess no professional background in your subject, so anything you do with my help will be your responsibility. Thank you for reading this, and have a wonderful day/night!
4 0
3 years ago
A uniform rod is 2.0 m long. The rod is pivoted about a horizontal, frictionless pin through one end. The moment of inertia of t
emmasim [6.3K]

Answer:

Angular acceleration = 6.37rad/sec²

Approximately, Angular acceleration =

6.4 rad/sec²

Explanation:

Length of the rod = 2.0m long

Inclination of the rod (horizontal) = 30°

Mass of the rod is not given so we would refer to it as = M

Rotational Inertia of the Rod(I) = 1/3ML²

Angular Acceleration = ?

There is an equation that shows us the relationship between Torque and Angular acceleration.

The equation is :

Torque(T) = Inertia × Angular Acceleration

Angular acceleration = Torque ÷ Inertia

Where:

Torque = L/2(MgCosθ)

Where M = Mass

L = Length = 2.0m

θ = Inclination of the rod (horizontal) = 30°

g = Acceleration due to gravity = 9.81m/s²

Inertia = 1/3ML²

Angular Acceleration =  (Mass × g × Cos (30°) × (L÷2)) ÷ 1/3ML²

Angular Acceleration =

(3 × g × cos 30°) ÷ 2× L

Angular Acceleration = (3 × 9.81m/s² × cos 30°) ÷ 2× L

Angular Acceleration = 3 × 9.81m/s² × cos 30°) ÷ 2× 2.0m

Angular Acceleration = 6.37rad/sec²

Approximately Angular Acceleration =

6.4rad/sec²

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