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Oksana_A [137]
3 years ago
14

Round 32.697 to the nearest tenth,hundredth,and one

Mathematics
2 answers:
tamaranim1 [39]3 years ago
7 0

We are given a decimal number 32.697.

First we need to round it to the nearest tenth.

Nearest tenth is upto one decimal place.

We can see, that number at 2nd digit on right side of decimal is 9 and that is greater than 4.

So, we need to increase first digit after decimal by 1.

<h3>So, it would become 32.7 ( nearest tenth).</h3>

Let us round it to hundredth place.

We can see, third decimal number is 7 and that is greater than 4.

So, we need to increase second digit after decimal by 1.

<h3>So, it would be 32.70 (nearest hundredth).</h3><h3 />

Let us round it to the one.

First number after decimal is 6, that is greater than 4.

Therefore , ones place number should be increase by 1.

<h3>So, it woud be 33 ( nearest ones).</h3>
Anastasy [175]3 years ago
6 0
Tenth 32.7
Hundredth 32.70
One 33
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Answer:

Yes

Step-by-step explanation:

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8 s + 3 g + 3k = 8

●For Zainab the equation will be:

4 s + 9 g + 4 k = 10.9

Take the first equation and divide both sides by 4 to make it easier.

You get:

● 2s + 0.75 g + 0.75k = 2

Take the second equation and divide both sides by 2 to make easier.

You get:

● 2s + 4.5g + 2k = 5.45

The new system of equation is:

● 2s +0.75g + 0.75k = 2

● 2s + 4.5g + 2k = 5.45

Express s in the first equation using the other variables.

● 2s +0.75g +0.75k = 2

● 2s + 0.75(g+k) = 2

● 2s = 2-0.75(g+k)

● s = 1- 0.325 (g+k)

Replace s by the new expression in the second equation:

●2 [1-0.325(g+k)] +4.5 g +2k = 5.45

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●2- 0.75g -0.75k +4.5 g +2k = 5.45

●2+ 3.75g + 1.25k = 5.45

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We have eliminated one variable (s)

We will keep (3.75g+1.25k=3.45) and use it.

Now that we eliminated in the second equation do it again in the first one.

You will get a system of equations with two variables.

Solve it and replace g and k with the solutions.

Finally solve the equation and find s.

8 0
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Simplify this question
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Step-by-step explanation:

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Step-by-step explanation:

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