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natima [27]
2 years ago
14

Elda has a rectangular piece of paper with an area of 0.12m squared. She cuts this piece of paper into small rectangles each wit

h an area of 200 cm squared. What is the maximum number of these small rectangles Elda can cut?
Mathematics
1 answer:
Lisa [10]2 years ago
7 0
The maximum number is 6. 

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Eighty-seven decreased by three times a number is greater than one hundred sixty-five
QveST [7]
The answer
the question is not clear
if it is to determine how to write this phrase as a mathematics equation, it is as follow:
let be x the unknown number
so <span>ighty-seven decreased by three times a number is greater than one hundred sixty-five means  87 - 3x>165, 
so we can solve it easily as 87 - 165> 3x, and then 3 x > 32, and finally the value of x is x > 32/3=10.66</span>
3 0
3 years ago
ANSWER QUICK AND WILL GIVE 1000 POITS PLEASE!!!!!!!A truck drove 229.77 miles on 11.1 gallons of gas. How far could the truck dr
Archy [21]

Answer:

  • 347.76 miles

Step-by-step explanation:

A truck drove 229.77 miles on 11.1 gallons of gas.

<u>Find the mileage per gallon:</u>

  • 229.77 / 11.1 = 20.7 mpg

<u>Find the distance can be driven on full tank:</u>

  • 20.7 * 16.8 = 347.76 miles
4 0
2 years ago
Read 2 more answers
A car is traveling at a speed of 25 meters per second what is the cars speed in kilometers per hour how many kilometers will the
Likurg_2 [28]

Answer:

  • 90 km/h
  • 180 km

Step-by-step explanation:

There are 1000 m in 1 km, and 3600 s in 1 h, so the speed conversion is ...

  \dfrac{25\,m}{s}\cdot\dfrac{1\,km}{1000\,m}\cdot\dfrac{3600\,s}{1\,h}=\dfrac{90\,km}{h}

The car's speed is 90 km/h.

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In 2 hours, the car will travel ...

  distance = speed · time = (90 km/h)(2 h) = 180 km

7 0
3 years ago
If you answer God will bless you:
VashaNatasha [74]

Answer:

600 m³

Step-by-step explanation:

Given:

  • length of swimming pool = 30 m
  • width of swimming pool = 10 m
  • depth at deep end = 3 m
  • depth at shallow end = 1 m

To find the volume of the water in the pool, find the area of a cross section (see attached image) and multiply it by the width of the pool.

<u>Area of cross section</u>

= area of rectangle - area of triangle

= (3 × 30) - [1/2 × 30 × (3 - 1)]

= 90 - 30

= 60 m²

<u>Volume of pool</u>

= area of cross section × width

= 60 × 10

= 600 m³

6 0
2 years ago
3(2^x) = 6^2x <br>How do you solve this?
iragen [17]
3(2^x)=6^{2x}
3(2^x)=(3\times2)^{2x}
3(2^x)=3^{2x}2^{2x}
\ln(3(2^x))=\ln(3^{2x}2^{2x})
\ln3+\ln2^x=\ln3^{2x}+\ln2^{2x}
\ln3+x\ln2=2x\ln3+2x\ln2
\ln3=2x\ln3+2x\ln2-x\ln2
\ln3=x(2\ln3+\ln2)
x=\dfrac{\ln3}{2\ln3+\ln2}
7 0
2 years ago
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