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icang [17]
3 years ago
5

Calculus The following curve passes through (3,1) Using linear lineralization

Mathematics
1 answer:
Novay_Z [31]3 years ago
6 0

Answer:

Option 1.1

Step-by-step explanation:

The linearization of a curve implies the use of calculus to find the local value for the derivative and approximating the function by the use of the formula

F(x) \approx F(x_0) + F'(x_0)(x-x_0)

The function is given in such way that it's much easier to find the derivative by implicit differentiation than isolating any of the variables

2x^2y+y=2x+13

Differentiating with respect to x, we have

4xy+2x^2y'+y'=2

Computing y' in the given point (3,1) we have

4(3)(1)+2(9)y'+y'=2

y'=\frac{2-12}{19}

y'=-\frac{10}{19}

The function will be approximated with the expression

F(x) = 1 -\frac{10}{19}(x-3)

To find the approximate value for x=2.8

F(2.8) = 1-\frac{10}{19}(-0.2)=1.1

The correct value is the option 1.1

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