31-62=152+2-6(3+21)
31-62=152+2-18+126
-31 =262
The function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
<h3>How to determine the function?</h3>
For a function to have its vertex on the y-axis, then the coordinate of the vertex must be:
(h,k) = (0,y)
A quadratic function is represented as:
f(x) = (x - h)^2 + k
So, we have:
f(x) = (x - 0)^2 + k
Evaluate
f(x) = x^2 + k
From the list of options, we have:
f(x) = (x - 2)(x + 2)
Expand
f(x) = x^2 - 4
Hence, the function that has a vertex on the y-axis is f(x) = (x - 2)(x + 2)
Read more about vertex at:
brainly.com/question/18797214
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Answer:
Step-by-step explanation:
In the given right triangle,
Measure of angle = x°
Opposite side of the angle = 12 units
Adjacent side of the angle = 6 units
By taking tangent ratio of the given angle,
tan(x°) = 
= 
= 2
One solution is (–1, <span> ⇒ 16</span>).
The second solution (2, <span> ⇒ 10</span>). your welcome
