Since x=8y, subsitute 8y for x in other equation
y=6x-11
y=6(8y)-11
y=48y-11
minus y both sides
0=47y-11
add 11 to both sides
11=47y
divide both sides by 47

subsitute taht for y to find x
x=8y




in (x,y) form
(x,y)
13x - y = 19
-y = - 13x + 19
y = 13x + 19
Answer:
The man wins 9 times and looses 11 times in the rock - paper-scissor game.
Step-by-step explanation:
Let us assume that in the game:
Number of times man wins the games = x times
Number of times man loses the games = y times
Total number of attempts = 20
Points after winning = 5
Points after loosing = 2
Now, according to the question:
x + y =20
and 5 x + 2 y = 67
Now, from (1) y = 20-x, put in (2)
5x + 2y = 67 ⇒ 5x + 2(20 -x) = 67
or, 5x -2x = 67 - 40
or, 3x = 27
⇒ x = 27/3 = 9
then y = 20 - x = 20 - 9 = 11
⇒ x = 9 and y = 11 is the solution of the given system.
Hence, the man wins 9 times and looses 11 times in the rock - paper-scissor game.
Answer:
The surface area of right regular hexagonal pyramid = 82.222 cm³
Step-by-step explanation:
Given as , for regular hexagonal pyramid :
The of base side = 3 cm
The slant heights = 6 cm
Now ,
The surface area of right regular hexagonal pyramid = 
Where a is the base side
And h is the slant height
So, The surface area of right regular hexagonal pyramid = 
Or, The surface area of right regular hexagonal pyramid = 
Or, The surface area of right regular hexagonal pyramid = 23.38 + 9 ×
∴ The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538
I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842
So, The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer
Answer:
Uh
Step-by-step explanation: