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polet [3.4K]
2 years ago
7

Whats the missing number

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
4 0

Answer:

<h2><u><em>5</em></u></h2>

Step-by-step explanation:

X * 3^2 +2 = 47

X * 9 + 2 = 47

9X = 47 - 2

9x = 45

x = 45 : 9

X = 5

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Since x=8y, subsitute 8y for x in other equation

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x=\frac{88}{47}
y=\frac{11}{47}
in (x,y) form
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3 years ago
Solve using the substitution method 8x-2y=-14 5x+y=33 show work
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13x - y = 19
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8 0
2 years ago
In a rock-paper-scissors game, a winner gets 5 points and a loser gets 2 points. After a man played this game 20 times, his tota
aleksandr82 [10.1K]

Answer:

The man wins 9 times and looses 11 times in the rock - paper-scissor game.

Step-by-step explanation:

Let us assume that in the game:

Number of times  man wins the games = x times

Number of times  man loses the games = y times

Total number of attempts = 20

Points after winning = 5

Points after loosing = 2

Now, according to the question:

       x  + y =20

and 5 x + 2 y = 67

Now, from (1) y = 20-x,     put in (2)

5x + 2y = 67       ⇒           5x + 2(20 -x)  = 67

or, 5x -2x = 67 - 40

or, 3x = 27

⇒ x = 27/3 = 9

then y = 20 - x = 20 - 9 = 11

⇒ x = 9 and y = 11 is the solution of the given system.

Hence, the man wins 9 times and looses 11 times in the rock - paper-scissor game.

3 0
3 years ago
find the surface area of a right regular hexagonal pyramid with sides 3 cm and slant heights 6cm. show all of your work.​
DedPeter [7]

Answer:

The surface area of right regular hexagonal pyramid = 82.222 cm³

Step-by-step explanation:

Given as , for regular hexagonal pyramid :

The of base side = 3 cm

The slant heights = 6 cm

Now ,

The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times a^{2} + 3 a \sqrt{h^{2}+ 3\times \frac{a^{2}}{4}}

Where a is the base side

And h is the slant height

So, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 3^{2} + 3 \times 3 \sqrt{6^{2}+ 3\times \frac{3^{2}}{4}}

Or, The surface area of right regular hexagonal pyramid = \frac{3\sqrt{3}}{2}\times 9 + 9 \sqrt{36+ 3\times \frac{9}{4}}

Or,  The surface area of right regular hexagonal pyramid = 23.38 + 9 × \frac{171}{4}

∴  The surface area of right regular hexagonal pyramid = 23.38 + 9 × 6.538

I.e The surface area of right regular hexagonal pyramid = 23.38 + 58.842

So,  The surface area of right regular hexagonal pyramid = 82.222 cm³ Answer

6 0
3 years ago
Find the distance between:<br> (-1,0) and (-12, -1)
Kazeer [188]

Answer:

Uh

Step-by-step explanation:

3 0
2 years ago
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