J, K, and L are collinear
J is between K and L
LK = KJ + LJ
LK = 9x + 7
KJ = 2x - 3
LJ = 4x - 8
9x + 7 = (2x - 3) + (4x - 8)
9x + 7 = (2x + 4x) + (-3 - 8)
9x + 7 = 6x + -11
9x + 7 = 6x - 11
9x + 7 - 7 = 6x - 11 - 7
9x = 6x - 18
9x - 6x = 6x - 6x - 18
3x = -18
x = -6
∴ The value of x is -6
0,-5 i hope this is can sorry if its wrong
Answer:
c
Step-by-step explanation:
Given the 2 equations
x + y = 3 → (1)
3x - y = 1 → (2)
Adding the 2 equations term by term will eliminate the term in y
4x = 4 ( divide both sides by 4)
x = 1
Substitute x = 1 into either of the 2 equations and evaluate for y
Substituting into (1)
1 + y = 3 ( subtract 1 from both sides )
y = 2
Solution is (1, 2 ) → c
