Answer:
there you go but im not sure . hope its helpful and good luck ;)
Answer:
A ≈ 35.3 units²
Step-by-step explanation:
Calculate the radius CB using Pythagoras' identity in the right triangle.
CB² + AB² = AC²
CB² + 6² = 9²
CB² + 36 = 81 ( subtract 36 from both sides )
CB² = 45 = r²
Then area of quarter circle is
A = 
× πr² = × π × 45 ≈ 35.3
radius of ½ circle = d : 2
= 6in : 2 = 3in
Total area = Rectangle area + ½Circle area + Triangle area
= (l×w) + ½(π×r²) + (½×b×h)
= (10×6) + ½(π×3²) + (½ × (14-10) × 6)
= 60 + 14.14 + 12 = 86.14in
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Answer : 86.14in</h3>
<em>See</em><em> </em><em>the</em><em> </em><em>bold</em><em> </em><em>one</em><em> </em><em>in</em><em> </em><em>line</em><em> </em><em>2</em><em> </em><em>of</em><em> </em><em>total</em><em> </em><em>area</em><em>,</em><em> </em><em>thats the</em><em> </em><em>formula</em><em> </em><em>of</em><em> </em><em>all</em><em> </em><em>shape</em><em>.</em>
Answer:
11 meters
Step-by-step explanation:
Lets say that w = width of the rectangle, to start. If the length of the rectangle is 3 meters greater than 2 times the width, the length of the rectangle is equal to 3 + 2w.
The perimeter of the rectangle is 2 * length of rectangle + 2 * width of the rectangle. With the perimeter being equal to 30 and width being w and length being 2w+3:
The perimeter of the rectangle is 2(w) + 2(2w+3) = 30.
We first need to find out w first, which will give us the width of the rectangle. Taking it step by step, we get:
2w + 4w + 6 = 30
6w + 6= 30
6w = 24 which is done by subtracting both sides by 6 to put the variables on one side and the values on the other side
w = 4 which is done by dividing 6 on both sides
Ultimately, this gets width to be 4 meters. Now that we found the width, we need to plug w = 4 into the equation we set up for length which is 2w+3.
That being said, the ANSWER is:
length of rectangle = 2(4)+3 = 11 meters
Hope this helps! :)
