The best choice would probaly be b but im not positive
if its not b then its a
Answer:
Correct answer: Nickels x = 11 and pennies y = 9
Step-by-step explanation:
We will first define the variables in the system:
Let be nickels x and pennies y
We will form a system to solve this problem:
5 x + 1 y = 64
x + y = 20/ · (-1)
we will first multiply the second equation by -1 and add it by the first and get:
4 x = 44 ⇒ x = 44 / 4 = 11 nickels
x = 11 nickels
from the other we get y
y = 20 - x = 20 - 11 = 9 pennies
y = 9 pennies
God is with you!!!
Answer:
266
Step-by-step explanation:
Let no. of main floor tickets = x
Balcony tickets = x + 100
4(x+100) + 12(x) = 3056
4x + 400 + 12x = 3056
16x = 3056-400
16x = 2656
x = 2656/16
x = 166
No. of Balcony tickets = x + 100 = 166 + 100 = 266
Answer:
from original question:
Step-by-step explanation:
To determine the future value for the 401(k), we need to determine the amount contributed annually. It is stated that the amount the employee contributes to the fund is 9% of $45,624. $45,624(0.09) = $4,106.16 The employer contributes a maximum of 3% of the employee contribution. Therefore: $45,624(0.03) = $1368.72. Therefore, the total annual contribution is $5,474.88, giving a future value of $196,302.40. For the Roth IRA, the monthly contributions are $352.45 giving a future value of $152,636.09. Therefore, the 401(k) has a greater future value by $43,666.31.
Answer:
765 J
Step-by-step explanation:
We are given;
Mass of bucket = 30 kg
Mass of rope = 0.3 kg/m
height of building= 30 meter
Now,
work done lifting the bucket (sand and rope) to the building = work done in lifting the rope + work done in lifting the sand
Or W = W1 + W2
Work done in lifting the rope is given as,
W1 = Force x displacement
W1 = (30,0)∫(0.2x .dx)
Integrating, we have;
W1 = [0.2x²/2] at boundary of 30 and 0
W1 = 0.1(30²)
W1 = 90 J
work done in lifting the sand is given as;
W2 = (30,0)∫(F .dx)
F = mx + c
Where, c = 30 - 15 = 15
m = (30 - 15)/(30 - 0)
m = 15/30 = 0.5
So,
F = 0.5x + 15
Thus,
W2 = (30,0)∫(0.5x + 15 .dx)
Integrating, we have;
W2 = (0.5x²/2) + 15x at boundary of 30 and 0
So,
W2 = (0.5 × 30²)/2) + 15(30)
W2 = 225 + 450
W2 = 675 J
Therefore,
work done lifting the bucket (sand and rope) to the top of the building,
W = 90 + 675
W = 765 J
