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nikitadnepr [17]
2 years ago
14

There’s more options btw but what’s the answer please

Mathematics
1 answer:
lianna [129]2 years ago
3 0

Answer:

  • 8

Step-by-step explanation:

(32)^{\frac{3}{5}}\\\\\\(2^{5})^{\frac{3}{5}}\\\\\\2^3\\\\\\ \to 8

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X+3= -10 what is x in the equation
Dvinal [7]
X=-13 hope this helps
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Find The Sum . Write the answer in simplest form .
KIM [24]
A. 7 7/9 is your answer.
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The cost of a ticket is $7. write an equation that relates to the total cost/c, for a particular number of tickets purchased. Id
Lady_Fox [76]
If we know the cost of a ticket is $7, we can then write an equation in slope-intercept form for the amount it will cost to buy any amount of tickets.

If we denote x as the amount of tickets purchased, and c as the total cost, we can write the equation:

c=7x

Since we can vary the amount of tickets purchased independently of the total amount, x (the amount of tickets purchased) will be the independent variable.

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HELP WITH ALL <br> Determine the composite functions of the following set of functions
elixir [45]

QUESTION 1

i) Given f(x)=5x-2 and g(x)=x^2.

(f\circ g)=f(g(x))

(f\circ g)=f(x^2)

We plug in x^2 into f(x)=5x-2

(f\circ g)=5x^2-2

ii) Given f(x)=5x-2 and g(x)=x^2.

(g\circ f)=g(f(x))

(g\circ f)=g(5x-2)

We plug in 5x-2 into g(x)=x^2

(g\circ f)=(5x-2)^2

(g\circ f)=25x^2-10x-10x+4

(g\circ f)=25x^2-20x+4

QUESTION 2

i) Given g(x)=x^2-4 and h(x)=\sqrt{2x+1}.

(h\circ g)=h(g(x))

(h\circ g)=h(x^2-4)

We plug in x^2-4 into h(x)=\sqrt{2x+1}

(h\circ g)=\sqrt{2(x^2-4)+1}

(h\circ g)=\sqrt{2x^2-8+1}

(h\circ g)=\sqrt{2x^2-7}

ii) Given g(x)=x^2-4 and h(x)=\sqrt{2x+1}.

(g\circ h)=g(h(x))

(g\circ h)=g(\sqrt{2x+1})

We plug in \sqrt{2x+1 into g(x)=x^2-4

(g\circ h)=(\sqrt{2x+1})^2-4

(g\circ h)=2x+1-4

(g\circ h)=2x-3

QUESTION 3

i) Given g(x)=x+5 and h(x)=\sqrt{x-4}.

(g\circ h)=g(h(x))

(g\circ h)=g(\sqrt{x-4})

We plug in \sqrt{x-4} into g(x)=x+5

(g\circ h)=\sqrt{(x-4)+5}

ii) Given g(x)=x+5 and h(x)=\sqrt{x-4}.

(g\circ g)=g(g(x))

(g\circ g)=g(x+5)

We plug in x+5 into g(x)=x+5

(g\circ g)=(x+5)+5}

(g\circ g)=x+10}

QUESTION 4

The given functions are;

f(x)=-2x+1 and g(x)=-x^2  

f\circ f=f(f(x))

f\circ f=f(-2x+1)

f\circ f=-2(-2x+1)+1)

f\circ f=4x-2+1)

f\circ f=4x-1)

ii)  

g\circ g=g(g(x))

g\circ g=g(-x^2)

g\circ g=-(x^2)^2

g\circ g=-x^4

QUESTION 5

f(x)=5x-2;g(x)=x^2;h(x)=-3x

h\circ g\circ f=h\circ (g(f(x))

h\circ g\circ f=h\circ (g(5x-2))

h\circ g\circ f=h\circ ((5x-2)^2)

h\circ g\circ f=h\circ (25x^2-20x+4)

h\circ g\circ f=h(25x^2-20x+4)

h\circ g\circ f=-3(25x^2-20x+4)

h\circ g\circ f=-75x^2+60x-12)

ii.

f\circ f\circ g=f\circ (f(g(x))

f\circ f\circ g=f\circ (f(x^2)

f\circ f\circ g=f\circ (5x^2-2)

f\circ f\circ g=f(5x^2-2)

f\circ f\circ g=5(5x^2-2)-2

f\circ f\circ g=25x^2-10-2

f\circ f\circ g=25x^2-12

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3 years ago
a golden eagle flies a distance of 290 miles in 5 days.if the eagle flies the same distance each day of its journey, how far doe
egoroff_w [7]
1450 per day jgjhfjvbjgvnbfhnfg <------ nothing ;)
6 0
3 years ago
Read 2 more answers
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