9/20
You need to have the same denominator so multiply it by 5 on the bottom and top to get 5/20 then you can compare it 5/20 < 9/20
It would be greater, because 1 foot is equal to 12 inches. 8 times 12 is 96. Then 96 plus 6 inches in 102. So it would be greater.
Answer:
The proportion of students whose height are lower than Darnell's height is 71.57%
Step-by-step explanation:
The complete question is:
A set of middle school student heights are normally distributed with a mean of 150 centimeters and a standard deviation of 20 centimeters. Darnel is a middle school student with a height of 161.4cm.
What proportion of proportion of students height are lower than Darnell's height.
Answer:
We first calculate the z-score corresponding to Darnell's height using:

We substitute x=161.4 ,
, and
to get:

From the normal distribution table, we read 0.5 under 7.
The corresponding area is 0.7157
Therefore the proportion of students whose height are lower than Darnell's height is 71.57%
Answer:
C
Step-by-step explanation: