The scale of a map is 2m=4mi map:12m actual is

Mathematics

1 answer:

8_murik_8 [283]3 years ago

5 0

The answer to this would be : 24miles. hope it helped you

You might be interested in

How to solve the problem

vladimir1956 [14]

Since the square roots are both six and cannot be simplified any more you just treat it like a normal subtraction problem
so -5 - 2= -7
so it would be -7√2

4 0

3 years ago

Can anyone help me with this?

dmitriy555 [2]

Okay this is the basic when there is a - + + = -

5 0

3 years ago

A parabolic microphone used on the sidelines of a professional football game uses a reflective dish 24 inches wide and 6 inches

Strike441 [17]

The answer is a.
When you are solving problems like this you would use the equation y^2=4ax. The x and Y would be the coordinates. Based on the equation you have given the coordinates would be (6,12) and (6,-12), (24 is split up evenly between the y-axis).
Then we go on to solve the equation by plugging in the numbers 12^2=4a(6)
144=24a
144/24=24a/24
6=a

5 0

3 years ago

How is angle a related to angle d? A) vertical angles B) alternate interior angles C) alternate exterior angles D) corresponding

Art [367]

Answer:

because they are across from each other vertically

Step-by-step explanation:

3 0

3 years ago

Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .

6 0

3 years ago