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Umnica [9.8K]
3 years ago
14

Alicia cashed her paycheck and used half her earning to take three friends to dinner. She spent $42.15 on dinner and she brought

home more than $20.00. Write an inequality to represent the situation, using x to represent the amount of Alicia’s paycheck.
Mathematics
1 answer:
kenny6666 [7]3 years ago
3 0

Answer:

x - $42.15 > $20.00

 + $42.15 + $42.15

             x > $62.15

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Determine whether the statement is always true, sometimes true, or never true. Give an example. (a) Both sides of an equation ca
arsen [322]

Answer:

(A) Always true

(B) Seldom true

Step-by-step explanation:

(A) Both sides of an equation can be multiplied by the same number without this action changing the solution of the equation.

Keyword here is "number".

Multiplying both sides of an equation by an equal quantity (same number) will result in same solution after solving for the unknown in the equation. This is because that numeric quantity can always be removed by dividing both sides of the equation by it or by a factor (or multiple) of it.

EXAMPLE:

For a linear equation, 4x - 6 = 15x

let's find the solution, in other words solve for the unknown value X.

4x - 15x = 6

-11x = 6

x = -6/11

Now multiply both sides of the equation by 3.

3(4x - 6) = 3(15x)

12x - 18 = 45x   ___new equation

Solve for X

12x - 45x = 18

-33x = 18

x = -18/33

Reduce the fraction to its simplest form by looking for a number that can divide both numerator and denominator without remainder. In other words, think of a number that is a factor of 18 and a factor of 33.

That common factor or highest common factor (HCF) is 3.

Go ahead and reduce the fraction.

x will be reduced to -6/11

(B) Both sides of an inequality can seldom be multiplied by the same number, without such action changing the solution set of the equation.

Inequalities are more complex. Operational signs even change sometimes, in the course of finding the solution set of the inequality.

Sometimes, multiplying both sides of an inequality by a given numeric quantity will change its solution set and sometimes, it won't.

5 0
3 years ago
6. Let A and B be nxn matrices . Compute (A + B) (A + B). Explain all steps.
Pie

Answer:

(A+B)(A+B)=A.A+B.A+A.B+B.B

Step-by-step explanation:

Given that matrices A and B are nxn matrices

We need to find (A+B)(A+B)

For understanding the multiplication of matrices let'take A is mxn and B is pxq matrices,we can multiple only when n=p,so our Ab matrices will be mxq.

We know that that in matrices AB is not equal to BA.

Now find  

(A+B)(A+B)=A.A+B.A+A.B+B.B

So from we can say that (A+B)(A+B) is not equal to A.A+2B.A+B.B because AB is not equal to BA in matrices.

So (A+B)(A+B)=A.A+B.A+A.B+B.B

4 0
3 years ago
Simplify expression (distributive property) 11(9+d) if correct I'll mark brainliest!
Juli2301 [7.4K]
11 x 9 is 99 so then you do 11 x d and that’s 11d so it would be 99+11d :)
3 0
2 years ago
Read 2 more answers
What is 7 1/12 - 2 3/4 in simplest form
stich3 [128]

7 1/12  -  2 3/4

First we have to change mixed numbers to improper fractions

7 1/12  =  7 x 12 + 1 = 85   85/12

2 3/4  =  2 x 4 + 3 =  11     11/4

 85/12 - 11/4

Now we need to find the LCD (least common denominator) for 4 and 12

4, 8, 12

12

12 is our LCD, so it becomes our new denominator

85/12 would stay the same because the denominator wasn't changed but for 11/4 our new denominator is 12, so our fraction will change.

11/4  =  33/12 

4 goes into 12, 3 times. What you do to the bottom, you do to the top.

3 x 11 = 33

3 x 4 = 12

So, our new fraction is 33/12.  Now we subtract

85/12  -  33/12  =  52/12

Now we convert back to a mixed number

52 ÷ 12 = 4 4/12 reduce

4 1/3

Hope this helps.


6 0
3 years ago
Fine the two consecutive whole numbers the square root is between: √(26) & √(60)
blondinia [14]
The consecutive number = 1,2 or 7,8 not 5,8 etc

whole number = 1,6,100 

square root of 60 = 7.746

so, if you want to know two consecutive whole numbers b/w swrt of 60
that would be

7 less than 7.6 less than 8

 
3 0
3 years ago
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