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Ksju [112]
3 years ago
11

Use inductive reasoning to describe the pattern. Then find the next two numbers in the pattern. 1, 4, 7, 10, . . .

Mathematics
1 answer:
Kisachek [45]3 years ago
6 0

Option a: add 3 to the previous term; 13, 16

Explanation:

The sequence is 1, 4, 7, 10, ....

We need to determine the next two terms of the sequence.

Hence to find the next two terms, first we shall find the common difference between every two terms.

Common difference between 1 and 4 = 4-1=3

Similarly, common difference between 4 and 7 = 7-4=3

Common difference between 7 and 10 = 10-7=3

Hence, the common difference is 3.

So, the next two terms will also have the same common difference 3.

To determine the next two terms, first we shall add 3 to the term 10, we get,

10+3=13

Similarly, adding 3 to the term 13, we get,

13+3=16

Thus, the sequence is 1, 4, 7, 10, 13, 16, .....

Thus, add 3 to the previous term; 13, 16

Hence, option a is the correct answer.

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I need to know what the answer to that question is and I need to know how to do it
mel-nik [20]

Answer:

\frac{59}{8}  or 7\frac{3}{8}

Step-by-step explanation:

\frac{80}{4}  - 12\frac{5}{8}

First you need to make the 12 5/8 into an improper fraction by multiplying 12 by 8 and then adding the total by 5.

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3 years ago
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A box has a volume of 308 cm cubed. Its height is 4 cm greater than its length. Its length is 3 cm greater than its width. What
kifflom [539]

Answer:

4 cm.

Step-by-step explanation:

Given:

A box has a volume of 308 cm cubed.

Its height is 4 cm greater than its length.

Its length is 3 cm greater than its width.

Question asked:

What is the width of the box?

<u>Solution</u>:

Let width  = x\ cm

Length = x+3\ cm

Height = x+3+4=x+7\ cm

<u>As we know:</u>

<u />Volume\ of\ box=length\times width\times height

308=(x+3)\times x\times(x+7)\\ \\ 308=(x^{2} +3x)(x+7)\\ \\ 308=x^{2} (x+7)+ 3x(x+7)\\ \\ 308=x^{3} +7x^{2} +3x^{2} +21x\\ \\ 308=x^{3} +10x^{2} +21x\\ \\ Subtract\ 308\ from\ both\ sides\\ \\ x^{3} +10x^{2} +21x-308=0\\ \\ factor\ left\ side\ of\ equation\\ \\ (x-4)(x^{2} +14x+77)=0\\ \\  Set\ factors\ equal\ to\ 0.\\ \\ x-4=0 \ or\  x^{2} +14x+77=0\\ \\ \\

As width can never be in negative, x= 4\ cm

By substituting the value:-

Width  = x\ cm = 4 cm

Thus, width of the box is 4 cm.

4 0
3 years ago
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