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Delicious77 [7]

2 years ago

5

While unpacking a box of canned vegetables, you notice that 3 out of 30 cans are dented. Select all the ways you can write “3 ou

t of 30.

1 answer:

gizmo_the_mogwai [7]2 years ago

3 0

Answer:

Step-by-step explanation:

3/10 + infinite number of fractions.

30%

0.3

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If the length of one leg of a right triangle is 3 and the hypotenuse is √34, what is the length of the other leg?

Elenna [48]

To answer this question you must use Pythagorean theorem

$a^{2} +b^{2}=c^{2}$

a and b are the legs (the sides that form a perpendicular/right angle)

c is the hypotenuse (the side opposite the right angle)

In this case...

a = 3

b = unknown

c = √34

^^^Plug these numbers into the theorem

$3^{2} +b^{2} =√34^{2}$

Simplify

9 + b² = 34

solve for b

$b^{2}$ = 25

Take the square root of both sides to cancel out the square from the b

√b² = √25

b = 5

Hope this helped!

~Just a girl in love with Shawn Mendes

3 0

3 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

erma4kov [3.2K]

Answer:

a) $n = 9604$

b) n = 381

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

a. Assume that nothing is known about the percentage of computers with new operating systems. n = ?

When we do not know the proportion, we use $\pi = 0.5$ , which is when we are going to need the largest sample size.

The sample size is n when M = 0.01.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.01\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.01}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.01})^{2}$

$n = 9604$

b. Assume that a recent survey suggests that 99% of computers use a new operating system. n = ?

Now we have that $\pi = 0.99$ . So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.01 = 1.96\sqrt{\frac{0.99*0.01}{n}}$

$0.01\sqrt{n} = 1.96*\sqrt{0.99*0.01}$

$\sqrt{n} = \frac{1.96*\sqrt{0.99*0.01}}{0.01}$

$(\sqrt{n})^{2} = (\frac{1.96*\sqrt{0.99*0.01}}{0.01})^{2}$

$n = 380.3$

Rouding up

n = 381

7 0

3 years ago

The cross-sectional areas of a right pyramid and a right cylinder are congruent. The right pyramid has a height of 10 units, and

Ilia_Sergeevich [38]

Answer:

The volume of the cylinder is 2.1 times the volume of the pyramid

Step-by-step explanation:

step 1

Find the volume of the pyramid

we know that

The volume of a right pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the base of pyramid

H is the height of the pyramid

we have

$H=10\ units$

substitute

$Vp=\frac{10}{3}B\ units^{3}$

step 2

Find the volume of the right cylinder

we know that

The volume of right cylinder is equal to

$V=BH$

where

B is the area of the base of cylinder

H is the height of the cylinder

we have

$H=7\ units$

substitute

$Vc=7B\ units^{3}$

step 3

Compare the volumes

we know that

The area of the base both figures are congruent

Find the ratio of their volumes

$\frac{Vp}{Vc}$

substitute

$\frac{Vp}{Vc}=\frac{(\frac{10}{3}B)}{7B}$

Simplify

$\frac{Vp}{Vc}=\frac{10}{21}$

$21Vp=10Vc\\\\Vc=2.1Vp$

therefore

The volume of the cylinder is 2.1 times the volume of the pyramid

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3 years ago

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Middle term of (x-4)(x-3)

kodGreya [7K]

The middle term is -x

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3 years ago

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What is 2+2-4 x 40-60<br> and the answer is...........????

Ira Lisetskai [31]

Answer:

-216

Step-by-step explanation:

use the rule bodmas

bracket,othersign, division, multiplication, addition, subtraction

7 0

2 years ago