Answer:
0.087
Step-by-step explanation:
Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:
= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:
X₅ ~ Poisson (20 (5/60))
X₅ ~ Poisson (1.6667)
Formula for computing probabilities for Poisson is as follows:
P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!
P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! = (e^-1.6667)((1.6667²)/3!)
P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)
P(X₅= 3) = (2.718^(-1.6667))0.46
P(X₅= 3) = 0.1889×0.46
P(X₅= 3) = 0.086894
P(X₅= 3) = 0.087
Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.
The line is solid and under the line is shaded
so the answer is A
Angie will now have 100 stuffed animals
Answer:
50% head and 50% tails.
Step-by-step explanation:
A coin only has two sides to flip on and is equally probably flip heads or tails. If you flipped the coin 20 times you could expect to flip 10 heads and 10 tails.
This is a binomial distribution with n = 5, p = 0.55, q = 1 - 0.55 = 0.45, x = 0, 1, 2, 3
P(x) = nCx p^x q^(n - x)
P(x ≤ 3) = 1 - P(x > 3) = 1 - [P(4) + P(5)]
P(4) = 5C4 x (0.55)^4 x (0.45) = 0.2059
P(5) = 5C5 x (0.55)^5 x 1 = 0.0503
P(x ≤ 3) = 1 - (0.2059 + 0.0503) = 1 - 0.2562 = 0.7438
