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Gnom [1K]
3 years ago
13

How much will you get paid if you work 28.5 hours for $7.75 per hour?

Mathematics
1 answer:
jonny [76]3 years ago
4 0

$220.87 , (it would be $220.88 if you have to round up though

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Can you please find the domain and the range
ohaa [14]

Answer:

  • domain: (-4, ∞)
  • range: [-4, ∞)

Step-by-step explanation:

The domain is the horizontal extent of the function. This function is defined for all values of x greater than (but not including) -4. Its domain is (-4, ∞).

__

The range is the vertical extent of the function. This function gives output values of any number greater than or equal to -4. Its range is [-4, ∞).

__

Interval notation uses square brackets when the value is included in the interval. It uses round brackets (parentheses) when the end value is not included in the interval. ∞ is not a number, so that end always gets a round bracket.

6 0
3 years ago
Milan runs 6 miles in 55 minutes. At the same rate, how many miles would he run in 44 minutes?
jarptica [38.1K]

Answer: 4.8 miles

Step-by-step explanation:

6/55 = x/44

55x = 6(44)

55x = 264

x = 264/55 = 4.8 miles

3 0
3 years ago
Find the future value of $3633.49 invested for 2 years at 4% compounded monthly? ​
SSSSS [86.1K]

Answer:

$290.68

Step-by-step explanation:

$3633.49 times 2 times 4% = $290.68

3 0
2 years ago
One serving of tortilla soup is 1 2/3 cups. A restaurant cook makes 50 cups
maw [93]
No there is not. 50 divided by 1 2/3 gives you 30 which means it can’t create 35 servings.
7 0
3 years ago
Suppose that the length of a phone call in minutes is an exponential random variable with parameter λ = 1/ 8. If someone arrives
Elis [28]

Answer:

a) P=0.535

b) P=0.204

c) P=0.286

Step-by-step explanation:

The exponential distribution is expressed as

F(x>t)=e^{-\lambda t}

In this example, λ=1/8=0.125 min⁻¹.

a) The probability of having to wait more than 5 minutes

F(x>5)=e^{-0.125*5}=e^{-0.625}=0.535

b) The probability of having to wait between 10 and 20 minutes

F(1020)=e^{-0.125*10}-e^{-0.125*20}\\\\F(10

c) The exponential distribution is memory-less, so it is independent of past events.

If you have waited 5 minutes, the probability of waiting more than 15 minutes in total is the same as the probability of waiting 15-5=10 minutes.

F(x>15|t^*=5)=F(x>15)/F(x>5)=\frac{e^{-0.125*15}}{e^{-0.125*5}}=e^{-0.125*(15-5)}\\\\ F(x>15|t^*=5)=e^{-0.125*(10)}=F(x>10)=0.286

5 0
3 years ago
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