It is the commutative property of addition
x^2 = 100...by taking the square root of both sides, this eliminates the ^2
x = (+-) sqrt 100
x = (+-) 10
so the values of x are -10 and 10
<span>To solve this problem, we can use this formula d = rd (distance = rates x time)
She runs at a speed of 9 mph and walks at a speed of 3 mph.
Her distance running is
d = 9tr
where tr is the time she spends running
Her distance walking is
d = 3tw
where tw is the time she spends walking
The distances are the same so
9tr = 3tw
We also know that the total time is 5 hours
tr + tw = 5
tr = 5-tw
Substitute this value of tr in the first equation
9tr = 3tw
9(5-tw) = 3tw
45-9tw = 3tw
45 = 12tw
3.75= tw
Denise will spend 3.75 hours (3 hours, 45 minutes) walking back and 1.25 hours (1 hour, 15 minutes) running.</span>
Answer:[m, m+d, m+2d, - - - - -, n]
Step-by-step explanation:
We know the formula for arithmetic progression is a_(n) = a_(1) + (n-1)d
Where a_(n) is the nth term of the sequence
a_(1) is the first term of the sequence
n is the number of the term like if we are talking about 7th term so the n is 7.
d is the difference between two successive terms.
For this problem we know our first term that is m, our last term that is n and our difference that is d.
For second term we will use the formula
a_(2) = m + (2-1)d
a_(2) = m + (1)d
a_(2) = m + d
Similarly,
a_(3) = m + (3-1)d
a_(3) = m + (2)d
a_(3) = m + 2d
