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Alex
3 years ago
7

write a simplified expression that expression that shows thesum of three consecutive numbers where n is the last number. substit

ute n=5 to test the expression. what are the three consecutive numbers? what is their sum?​
Mathematics
2 answers:
kkurt [141]3 years ago
4 0

Answer: i dont know

Step-by-step explanation: hello im only here to complete a task, im receiving 50 points. I hope someone else can help you, cause I cant ;-;

blagie [28]3 years ago
3 0
<h3> ♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ The last number : n

The second number : n - 1

The third number : n - 2

n + n - 1 + n - 2

Simplify this:

3n - 3

Substitute 5 into it:

n = 5

n - 1 = (5) - 1 = 4

n - 2 = (5) - 2 = 3

3(5) - 3 = 12

Their sum is 12

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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fgiga [73]
The simple answer is 2.25/25
4 0
3 years ago
I need help please.
Rudiy27

Answer:

0.167, 0.164, 0.16

Step-by-step explanation:

In decimals, the closer it is to 1 the larger it gets. 0.167 is smaller than 0.164 because 0.164 is closer to one, which makes it greater.

8 0
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PLEASE HELP ME AND DONT JOKE AROUND
VladimirAG [237]

Answer:

12

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten
Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

Q(t) = Q(0)e^{-rt}

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that Q(12) = 0.5Q(0)

So

Q(t) = Q(0)e^{-rt}

0.5Q(0) = Q(0)e^{-12r}

e^{-12r} = 0.5

\ln{e^{-12r}} = \ln{0.5}

-12r = \ln{0.5}

12r = -\ln{0.5}

r = -\frac{\ln{0.5}}{12}

r = 0.05776

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

Q(t) = Q(0)e^{-rt}

50 = 200e^{-0.05776t}

e^{-0.05776t} = 0.25

\ln{e^{-0.05776t}} = \ln{0.25}

-0.05776t = \ln{0.25}

0.05776t = -\ln{0.25}

t = -\frac{\ln{0.25}}{0.05776}

t = 24

It would take 24 minutes for the element to decay to 50 grams

6 0
3 years ago
A triangle has an area of 36 cm². The base and height are scaled by a factor of 5.
Tatiana [17]
36÷3=12 12×5=60(the area of the resulting triangle)
4 0
3 years ago
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