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Evgen [1.6K]
2 years ago
15

Can someone help me with this please

Mathematics
1 answer:
Firdavs [7]2 years ago
6 0

Answer:

D

Step-by-step explanation:

A function input can only have ONE output value

so the number 5 can't output two different numbers

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The center of a circle is at (2, -5) and it's radius is 12. What is the equation of the circle?
Svetach [21]
The equation for a circle is (x-h)^2 +(y-k)^2=r^2
You just have to plug in your coordinates h is the x and k is the y.
The r is radius squared.
so, (x-2)^2+(y-(-5)^2=144
You have to be careful of those tricky negative values. When you distribute the y-(-5) it turns into y+5. 
So your answer is D.
8 0
3 years ago
Read 2 more answers
How do I put y=90-15x in standard form
lisabon 2012 [21]

The standard form: Ax + By = C


y = 90 - 15x     <em>add 15x to both sides</em>

<h3>15x + y = 90</h3>
8 0
3 years ago
What is the value of X?
bearhunter [10]
Let's solve this problem step-by-step.

STEP-BY-STEP SOLUTION:

Let's first establish that the shape is a triangle meaning that the following formula is applicable as displayed below:

Angle sum of a triangle = 180°

As well as this, the shape is an equilateral triangle meaning that each angle of the triangle is equivalent in value. Also, the following formula is also applicable as displayed below:

Each angle of an equilateral triangle = the same value

Therefore:

Each angle of an equilateral triangle = angle sum of a triangle ÷ no. of angles in a triangle = 180° ÷ 3 = 60°

Based on this, the following is applicable:

2x - 4 = 60°

2x = 60 + 4

2x = 64

x = 64 / 2

x = 32°

ANSWER:

Therefore, the answer is:

The value of ( x ) is 32°


Please mark as brainliest if you found this helpful! :)
Thank you <3
8 0
3 years ago
Which is a perfect square?<br> 0 5<br> 0 8<br> 36<br> 44
Liono4ka [1.6K]

Answer:

C) 36

Step-by-step explanation:

Because 6^2=6*6=36.

3 0
3 years ago
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16. (it’s a triangle)<br> x<br> x + 4<br> X-1<br> x + 2<br> what is x?
grigory [225]

Answer:

im sorry i don't know the answer i just need to do this so that i can ask my question pls forgive me

6 0
3 years ago
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