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mote1985 [20]
3 years ago
8

What are the least common multiple for one fourth and two thirds

Mathematics
2 answers:
bekas [8.4K]3 years ago
8 0
The least common multiple of the given numbers is 12
Assoli18 [71]3 years ago
3 0
Assuming that you want to add or subtract them and want the bottom number the same,

1/4 and 2/3

least common multiple of 4 and 3

4=2 times 2
3=3 times 1
so the leas common mulltiple will include all of them
the number is 2 times 2 times 3 or 12

lcm=12

1/4 times 3/3=3/12
2/3 times 4/4=8/12

add or subtract 3 and 8

LCM=12
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Find a formula for the function whose graph is given below.
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5 0
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Which graph shows a linear function? ​
Stolb23 [73]

Answer:

Step-by-step explanation:

You have shared only one graph, that of a quadratic function with vertex at (0, 0) and an equation based upon y = ax^2, where a is a constant coefficient.

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The graph that shows a straight line is the linear function.

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3 years ago
Graph the image of the given triangle under a dilation with a scale factor of 1/4 and center of dilation ​(0, 0)
schepotkina [342]

Answer:

The image in the attached figure

Step-by-step explanation:

we know that

The dimensions of the image of the given triangle are equal to the original dimensions of the pre-image multiplied by the scale factor

In this problem the scale factor is 1/4

The height of the pre-image is 4 units

The base of the pre-image is 8 units

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6 0
3 years ago
Suppose approximately 75% of all marketing personnel are extroverts, whereas about 70% of all computer programmers are introvert
Setler [38]

Answer:

P(x \ge 5) = 1.000 ---- At least 5 from marketing departments are extroverts

P(x=15) = 0.013 ---- All from marketing departments are extroverts

P(x = 0) = 0.002 ---------- None from computer programmers are introverts

Step-by-step explanation:

See comment for complete question

The question is an illustration of binomial probability where

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

(a):\ P(x \ge 5)

n = 15 --- marketing personnel

p = 75\% --- proportion that are extroverts

Using the complement rule, we have:

P(x \ge 5) = 1 - P(x < 5)

So, we have:

P(x < 5) =P(x = 0) + P(x = 1) + P(x = 2) + P(x = 3) + P(x = 4)

P(x = 0) = ^{15}C_{0} * (75\%)^0 * (1 - 75\%)^{15 - 0} = 1 * 1 * (0.25)^{15} = 9.31 * 10^{-10}

P(x = 1) = ^{15}C_{1} * (75\%)^1 * (1 - 75\%)^{15 - 1} = 15* (0.75)^1 * (0.25)^{14} = 4.19 * 10^{-8}

P(x = 2) = ^{15}C_{2} * (75\%)^2 * (1 - 75\%)^{15 - 2} = 105* (0.75)^2 * (0.25)^{13} = 8.80 * 10^{-7}

P(x = 3) = ^{15}C_{3} * (75\%)^3 * (1 - 75\%)^{15 - 3} = 455* (0.75)^2 * (0.25)^{12} = 0.0000153

P(x = 4) = ^{15}C_{4} * (75\%)^4 * (1 - 75\%)^{15 - 4} = 1365 * (0.75)^4 * (0.25)^{11} = 0.000103

So, we have:

P(x < 5) = (9.31 * 10^{-10}) + (4.19 * 10^{-8}) + (8.80 * 10^{-7}) + 0.0000153 + 0.000103

P(x < 5) = 0.00011922283

Recall that:

P(x \ge 5) = 1 - P(x < 5)

P(x \ge 5) = 1 - 0.00011922283

P(x \ge 5) = 0.9998

P(x \ge 5) = 1.000 --- approximated

(b)\ P(x = 15)

n = 15 --- marketing personnel

p = 75\% --- proportion that are extroverts

So, we have:

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

P(x=15) = ^{15}C_{15} * 0.75^{15} * (1 - 0.75)^{15-15}

P(x=15) = 1 * 0.75^{15} * (0.25)^{0

P(x=15) = 0.013

(c)\ P(x = 0)

n=5 ---------- computer programmers

p = 70\% --- proportion that are introverts

So, we have:

P(x) = ^nC_x * p^x * (1 - p)^{n-x}

P(x = 0) = ^{5}C_0 * (70\%)^0 * (1 - 70\%)^{5-0}

P(x = 0) = 1 * 1 * (0.30)^5

P(x = 0) = 0.002

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2 years ago
Question 1<br> 5/6<br> Minus<br> 1/4
taurus [48]

Answer:

1 7/12

Step-by-step explanation:

here you go :)

4 0
2 years ago
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