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Yuri [45]
3 years ago
10

William bought some tickets to see his favorite singer. He bought some adult tickets and some children’s tickets, for a total of

15 tickets. The adult tickets cost $30 per ticket, and the children’s tickets cost $20 per ticket. If he spent a total of $270, then how many adult and children’s tickets did he buy
Mathematics
1 answer:
Fantom [35]3 years ago
8 0
Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
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\red{ \boxed{ \boxed{ \tt{Our \: final \: answer :  \boxed{ \tt{5 {x}^{3}  - 2 {x}^{2}  + x - 2}}}}}}

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