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kykrilka [37]
3 years ago
11

Fran swims at a speed of 2.8 mph in still water. The Lazy River flows at a speed of 0.8 mph. How long will it take Fran to swim

4 mi​ upstream? 4 mi​ downstream?
Mathematics
1 answer:
Elis [28]3 years ago
7 0

Answer:

1.49 hrs or 1 hr and 30 minutes approximately

Step-by-step explanation:

if fran go 2.8m up then the river flow at a rate of 0.8m; the since we are taking the speed of fran and river to be constant. the ratio between their speed will always remain constant. that is if 0.8/2.8 = 0.286≈ this will be always constant.

so if he go up 4m then the horizontal length has to be 1.143 because 1.143/4 = 0.286.

now we find the distance between frans initial positon and final position. to find it we use pythagoras theorem.

\sqrt{(4^2 + 1.143^2)} =4.160 miles

to find the time divide distance traveled by speed;

4.160/2.8 = 1.49 hrs

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